Answer:
The mass of the lead will be "1.127 kg".
Explanation:
The given values are:
(Ice) m₁ = 50 g i.e.,
0.050 kg
(Water) m₂ = 195 g i.e.,
0.190 kg
(Copper cup) m₃ = 100 g i.e.,
0.100 kg
m₁, m₂ and m₃ at temperature,
t₁ = 0°C
Temperature of lead,
t₂ = 96°C
Temperature of Final equilibrium,
t₃ = 12°C
Let m₄ be the mass of the lead.
On applying formula, we get
⇒
On putting the estimated values, we get
⇒
⇒
⇒
⇒
⇒
Answer:
amount of energy = 4730.4 kWh/yr
amount of money = 520.34 per year
payback period = 0.188 year
Explanation:
given data
light fixtures = 6
lamp = 4
power = 60 W
average use = 3 h a day
price of electricity = $0.11/kWh
to find out
the amount of energy and money that will be saved and simple payback period if the purchase price of the sensor is $32 and it takes 1 h to install it at a cost of $66
solution
we find energy saving by difference in time the light were
ΔE = no of fixture × number of lamp × power of each lamp × Δt
ΔE is amount of energy save and Δt is time difference
so
ΔE = 6 × 4 × 365 ( 12 - 9 )
ΔE = 4730.4 kWh/yr
and
money saving find out by energy saving and unit cost that i s
ΔM = ΔE × Munit
ΔM = 4730.4 × 0.11
ΔM = 520.34 per year
and
payback period is calculate as
payback period =
payback period =
payback period = 0.188 year