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OLEGan [10]
3 years ago
10

Which ball will require the most force to lift?

Physics
2 answers:
Sholpan [36]3 years ago
8 0

The heaviest one will, if none of the others is stuck down with glue or sitting in cement.

KengaRu [80]3 years ago
6 0
A bowling ball because of the force it has one everyone on
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A ball of mass 0.600 kg is carefully balanced on a shelf that is 2.20 m above the ground. What is its gravitational potential en
katovenus [111]

Answer:

Explanation:

Gravitational potential energy = mass x height of object x g

g is gravitational acceleration .

Gravitational potential energy of the ball = .600 x 2.20 x 9.8

= 12.936 J .

12.9 J .

4 0
3 years ago
A force F moves a load from the bottom of a slope to the top
marysya [2.9K]

Answer:

i think A

Explanation:

3 0
3 years ago
A tetrahedron has an equilateral triangle base with 25.0-cm-long edges and three equilateral triangle sides. The base is paralle
KATRIN_1 [288]

Answer:

electric flux through the three side = 2.35 N m²/C

Explanation:

given,

equilateral triangle of base = 25 cm

electric field strength = 260 N/C

Area of triangle = \dfrac{\sqrt{3}}{4}a^2

                          =  \dfrac{\sqrt{3}}{4} 0.25^2

                          = 0.0271 m³

electric flux = E. A

                   = 260 × 0.0271

                   = 7.046 N m²/C

since, tetrahedron does not enclose any charge so, net flux through tetrahedron is zero.

electric flux through the three side = (electric flux through base)/3

                               = \dfrac{7.046}{3}

electric flux through the three side = 2.35 N m²/C

4 0
3 years ago
2. What will be the extension of this spring if the load is a) 4N and b) 75 g?
Furkat [3]

Answer:

6

Explanation:

just add

7 0
3 years ago
Some Physics questions! Please help!
lesantik [10]

1) 260 km/h

Let's use the following convention:

positive x-direction = east

positive y-direction = north

Here we have to find the north component of the velocity's airplane, which means we have to find its y-component.

We can use the formula:

v_y = v sin \theta

where

v = 750 km/h is the magnitude of the plane's velocity

\theta=20.0^{\circ} is the angle between the direction of the plane and the positive x-axis

Substituting,

v_y = (750)(sin 20)=256.5 km/h \sim 260 km/h

2) 24^{\circ} north of east

In order to find the direction of flight, we have to consider that the vector representing the displacement of the plane is the hypothenuse of a right triangle, of which the displacements along the east and north direction are the sides.

Therefore, we have

v_x = 220 km is the displacement towards east

v_y = 100 km is the displacement towards north

Therefore, the angle that gives the direction is given by

tan \theta = \frac{v_y}{v_x}

And substituting,

\theta =tan^{-1}( \frac{100}{200})=24^{\circ}

and this angle is measured north of east.

7 0
4 years ago
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