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Andru [333]
2 years ago
10

What subatomic particle is responsible for the observed properties of an atom?

Chemistry
2 answers:
Masteriza [31]2 years ago
7 0
The subatomic particle that is responsible for the observed properties of an atom is

A protons
Drupady [299]2 years ago
4 0
Protons are responsible for the observed properties of an atom
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An aquarium ecosystem is shown below. A community within this ecosystem consists of the:
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____ bonds are formed by the transfer of electrons from one atom to another atom, to form ____ and _____ ions.
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ionic, positive, negative

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2 years ago
A solution is saturated in both nitrogen gas N2 and sodium iodide NaI at 50 degree Celsius. When the solution is cooled to 25 de
xxMikexx [17]

Answer:

b. some sodium iodide will precipitate out of solution

Explanation:

We know that for salts solubility decreases as the temperature of the solution decreases. So, NaI being a salt, its solubility will surely decrease when the temperature is cooled down to 25°C from 50°C.

Thus,the undissolved sodium iodide will precipitate out of the solution.

6 0
3 years ago
How many grams of H2S is needed to produce 18.00g of PbS if the H2S is reacted with an
goldenfox [79]

Answer:

2.56 grams of H₂S is needed to produce 18.00g of PbS if the H2S is reacted with an  excess (unlimited) supply of Pb(CH₃COO)₂

Explanation:

The balanced reaction is:

Pb(CH₃COO)₂ + H₂S → 2 CH₃COOH + PbS

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) they react and produce:

  • Pb(CH₃COO)₂: 1 mole
  • H₂S: 1 mole
  • CH₃COOH: 2 moles
  • PbS: 1 mole

In this case,  to know how many grams of H₂S are needed to produce 18.00 g of PbS, it is first necessary to know the molar mass of the compounds H₂S and PbS and then to know how much it reacts by stoichiometry. Being:

  • H: 1 g/mole
  • S: 32 g/mole
  • Pb: 207 g/mole

The molar mass of the compounds are:

  • H₂S: 2* 1 g/mole + 32 g/mole= 34 g/mole
  • PbS: 207 g/mole + 32 g/mole= 239 g/mole

So, by stoichiometry they react and are produced:

  • H₂S: 1 mole* 34 g/mole= 34 g
  • PbS: 1 mole* 239 g/mole=   239 g

Then the following rule of three can be applied: if 239 grams of PbS are produced by stoichiometry from 34 grams of H₂S, 18 grams of PbS from how much mass of H₂S is produced?

mass of H_{2} S=\frac{18 grams of PbS*34 grams of H_{2}S }{239 grams of PbS}

mass of H₂S= 2.56 grams

<u><em>2.56 grams of H₂S is needed to produce 18.00g of PbS if the H2S is reacted with an  excess (unlimited) supply of Pb(CH₃COO)₂</em></u>

8 0
3 years ago
What is the maximum number of moles of H2O that can be produced from the reaction of 5.6 mol H2 and 4.7 mol O2?
Finger [1]

Answer:

The maximum number of moles of H2O is 5.8

Limiting Reactant: Oxygen

Excess Reactant: Hydrogen

Explanation:

8 0
3 years ago
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