Consider four elements from Group 7A: fluorine in the second period, chlorine in the third period, bromine in the fourth period,

Question

3 years ago

12

Consider four elements from Group 7A: fluorine in the second period, chlorine in the third period, bromine in the fourth period,

and iodine in the fifth period. Which element has the largest first ionization energy?
A.fluorine
B.chlorine
C.bromine
D.iodine
E.You need more data to predict the first ionization energy of these elements.

Chemistry

2 answers:

madam [21] · Answer 1 · 2022-01-01T04:41:03+03:00

Onization energy is the energy required to lose an electron and form an ion. The stronger is the attraction of the atom and the electron the higher the ionization energy, and the weaker is the attraction of the atom and the electron the higher the ionization energy. This leads to a clear trend in the periodic table. Given that the larger the atom the weaker the attraction of the atom to the valence electrons, the easier they will be released, and the lower the ionization energy. This is, as you go downward in a group, the ionization energy decreases. So, the element at the top of the group will exhibit the largest ionization energy. <span>Therefore, the answer is that of the four elements of group 7A, fluorine will have the largest first ionization energy.</span>

Lerok [7] · Answer 2 · 2022-01-01T06:15:17+03:00

Lerok [7]3 years ago

5 0

Answer:

A.fluorine

Explanation:

Plato