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Troyanec [42]
3 years ago
12

Consider four elements from Group 7A: fluorine in the second period, chlorine in the third period, bromine in the fourth period,

and iodine in the fifth period. Which element has the largest first ionization energy?
A.fluorine
B.chlorine
C.bromine
D.iodine
E.You need more data to predict the first ionization energy of these elements.
Chemistry
2 answers:
madam [21]3 years ago
7 0
Onization energy is the energy required to lose an electron and form an ion. The stronger is the attraction of the atom and the electron the higher the ionization energy, and the weaker is the attraction of the atom and the electron the higher the ionization energy. This leads to a clear trend in the periodic table. Given that the larger the atom the weaker the attraction of the atom to the valence electrons, the easier they will be released, and the lower the ionization energy. This is, as you go downward in a group, the ionization energy decreases. So, the element at the top of the group will exhibit the largest ionization energy. <span>Therefore, the answer is that of the four elements of group 7A, fluorine will have the largest first ionization energy.</span>
Lerok [7]3 years ago
5 0

Answer:

A.fluorine

Explanation:

Plato

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The value of the solubility product constant for Ag2CO3 is 8.5 × 10‒12 and that of Ag2CrO4 is 1.1 × 10‒12. From this data, what
Lena [83]

Answer:

B) 7.7

Explanation:

For the reaction    Ag2CO3(s) + CrO42‒(aq) → Ag2CrO4(s) + CO32‒(aq)

Kc = (CO₃²⁻) / (CrO₄²⁻)

and the Ksp given are

Ag₂CO₃    ⇒  2 Ag⁺(aq) + CO₃²⁻(aq)    Ksp₁ = (Ag⁺)²(CO₃²⁻)  

Ag₂CrO₄   ⇒  2 Ag⁺(aq)+ CrO₄²⁻(aq)   Ksp₂ = (Ag⁺)²(CrO₄²⁻)

Where (...) indicate concentrations M

Notice if we divide the expressions for Ksp we get:

Ksp₁/Ksp₂ = (CO₃²⁻)  / (CrO₄²⁻) = 8.5 x 10⁻¹² / 1.1 x 10⁻¹² = 7.7

which is the desired answer.

7 0
3 years ago
If the molecule C6H12 does not contain a double bond, and there are no branches in it, what will its structure look like?
NARA [144]
I have attached a photo of the structure. 
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5 0
3 years ago
Write formulas for the binary ionic compounds formed between the following elements: a. Potassium and iodine b. Magnesium and ch
lianna [129]

i think it's B Magnesium and chlorine



5 0
3 years ago
Consider the element carbon. How many electrons can be found in a carbon atom? How many are valence electrons?
Eva8 [605]

Answer:

option B= 6 : 4

Explanation:

Properties:

1. Carbon have six electron and six proton.

2. The two electrons are present in first shell while remaining of four electrons are present in the second shell.

3. it is non-metallic element and present in the group fourteen of periodic table.

4. its atomic mass is 12.0107 u.

5. its melting and boiling point is 3550 °C and 4827 °C respectively.

Uses:

1. it is used as a fuel in the form of coal.

2. in the form of graphite it is used in dry cells, as a lubricant, in pencil and high temperature crucible.

3. it is also used in jewelry in the form of diamond and because of its hard nature used in industries for drilling, polishing, cutting and grinding.

4. carbon black powder is used in printer ink.

5. its most common alloy with iron is steel.

6. it form variety of compound with number of other elements like nitrogen, hydrogen, oxygen etc.

Electronic configuration:

1s2, 2s2, 2p2

Isotopes of carbon:

There are fifteen isotopes of carbon from C8 - C22. The isotopes  C12 and C13 are stable while C14 is radioactive.

4 0
3 years ago
5. Why did you categorize the reactions the way you did? What do your physical reactions have in common? What do your chemical r
lapo4ka [179]

Answer:

What r u trying to ask? you need to put more stuff in your question on here so we can answer it.

Explanation:

7 0
3 years ago
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