Answer:
It heats up.
Explanation:
Because thermal energy is based off the temperature of an object and the average kinetic energy of its particles increases. When the average kinetic energy of its particles increases, the object's thermal energy increases. Therefore, the thermal energy of an object increases as its temperature increase.
Answer:
Both are endothermic reactions.
Explanation:
Chemical equation:
1/2H₂(g) + 1/2I₂(g) → HI(g) + 6.2 kcal/mol
Chemical equation:
21.0 kcal/mol + C(s) + 2S(s) → CS₂
Both reaction are endothermic because heat is added in both of reactions.
Endothermic reactions:
The type of reactions in which energy is absorbed are called endothermic reactions.
In this type of reaction energy needed to break the bond are higher than the energy released during bond formation.
For example:
C + H₂O → CO + H₂
ΔH = +131 kj/mol
it can be written as,
C + H₂O + 131 kj/mol → CO + H₂
Exothermic reaction:
The type of reactions in which energy is released are called exothermic reactions.
In this type of reaction energy needed to break the bonds are less than the energy released during the bond formation.
For example:
Chemical equation:
C + O₂ → CO₂
ΔH = -393 Kj/mol
it can be written as,
C + O₂ → CO₂ + 393 Kj/mol
the 1st one is balanced, the 2nd isn't (the number of Mg differs from left 1 to right 2).
The third is also not balanced, 2 F left,2*3=6 on the right
Answer:
is the value of the rate constant.
Explanation:
Let the order of the reaction be x.
The rate law of the reaction can be written as:
![R=k[H_2O_2]^x](https://tex.z-dn.net/?f=R%3Dk%5BH_2O_2%5D%5Ex)
1. Rate of the reaction when concentration changes from 0.882 M to 0.697 M in 0 seconds to 60 seconds.
![0.00308 M/s=k[0.697 M]^x](https://tex.z-dn.net/?f=0.00308%20M%2Fs%3Dk%5B0.697%20M%5D%5Ex)
..[1]
2. Rate of the reaction when concentration changes from 0.697 M to 0.566 M in 240 seconds to 360 seconds.
![0.00218 M/s=k[0.236 M]^x](https://tex.z-dn.net/?f=0.00218%20M%2Fs%3Dk%5B0.236%20M%5D%5Ex)
..[2]
[1] ÷ [2]
![\frac{0.00308 M/s}{0.00227 M/s}=\frac{k[0.697 M]^x}{k[0.236M]^x}](https://tex.z-dn.net/?f=%5Cfrac%7B0.00308%20M%2Fs%7D%7B0.00227%20M%2Fs%7D%3D%5Cfrac%7Bk%5B0.697%20M%5D%5Ex%7D%7Bk%5B0.236M%5D%5Ex%7D)
Solving fro x:
x = 0.92 ≈ 1
![R=k[H_2O_2]^1](https://tex.z-dn.net/?f=R%3Dk%5BH_2O_2%5D%5E1)
![0.00308 M/s=k[0.697 M]^1](https://tex.z-dn.net/?f=0.00308%20M%2Fs%3Dk%5B0.697%20M%5D%5E1)
![k=\frac{0.00308 M/s}{[0.697 M]^1}=0.00442 s^{-1}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B0.00308%20M%2Fs%7D%7B%5B0.697%20M%5D%5E1%7D%3D0.00442%20s%5E%7B-1%7D)
is the value of the rate constant.
The answer to this is hydrocarbons
