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Mrrafil [7]
3 years ago
7

Draw the structure of 4-chlorophthalic acid in the window below.

Chemistry
2 answers:
neonofarm [45]3 years ago
6 0
The structure of <span>4-chlorophthalic acid is attached below:

4-chlorophthalic acid is a dibasic acid i.e. it has 2 replaceable hydrogen atom. As compared to mineral acids, it is a weak acid. However, as compared to aliphatic acid, it is a strong acid. This is because of resonance effect. 
</span><span>
</span>

skelet666 [1.2K]3 years ago
3 0

Answer:

The Molecular formula of the 4-chloropthalic acid:Cl-C_6H_3-(COOH)_2

Explanation:

In 4-chloropthalic acid the main the skeleton in the molecule is benzene ring.

In benzoic acid the one more carboxylic group is present at ortho position and one chloro group is present at para position of the ring.

The structure of the 4-chloropthalic acid is given in an image.

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Why do we perform an experiment?
7nadin3 [17]

Answer:

Experiment plays many roles in science. One of its important roles is to test theories and to provide the basis for scientific knowledge. It can also call for a new theory, either by showing that an accepted theory is incorrect, or by exhibiting a new phenomenon that is in need of explanation.

Explanation:

6 0
3 years ago
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Write a nuclear reaction for the neutron-induced fission of u?235 to produce te?137 and zr?97. how many neutrons are produced in
alexandr1967 [171]
This is a neutron induced fission, therefore a neutron will be added to the U²³⁵ to cause the reaction, and thus it will be added to the left side. There will be unknown number of neutrons produced and thus we put this on the right hand side.
n₁ + U²³⁵ = Te¹³⁷ + Zr ⁹⁷ + xn1 ( n1 to mean a neutron of mass 1)
To balance the masses on both sides of the equation;
1 + 235 = 137 +97+ x
x = 2 
the end reaction will be
n₁ +U²³⁵ = Te¹³⁷ + Zr⁹⁷ + 2 n₁

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3 years ago
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What is the mass of 3.77mol of K3N?
AleksAgata [21]
<h3>Answer:</h3>

495 g K₃N

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.77 mol K₃N

<u>Step 2: Identify Conversions</u>

Molar Mass of K - 39.10 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of K₃N - 3(39.10) + 14.01 = 131.31 g/mol

<u>Step 3: Convert</u>

  1. Set up:                       \displaystyle 3.77 \ mol \ K_3N(\frac{131.31 \ g \ K_3N}{1 \ mol \ K_3N})
  2. Multiply/Divide:         \displaystyle 495.039 \ g \ K_3N

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

495.039 g K₃N ≈ 495 g K₃N

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