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Mrrafil [7]
3 years ago
7

Draw the structure of 4-chlorophthalic acid in the window below.

Chemistry
2 answers:
neonofarm [45]3 years ago
6 0
The structure of <span>4-chlorophthalic acid is attached below:

4-chlorophthalic acid is a dibasic acid i.e. it has 2 replaceable hydrogen atom. As compared to mineral acids, it is a weak acid. However, as compared to aliphatic acid, it is a strong acid. This is because of resonance effect. 
</span><span>
</span>

skelet666 [1.2K]3 years ago
3 0

Answer:

The Molecular formula of the 4-chloropthalic acid:Cl-C_6H_3-(COOH)_2

Explanation:

In 4-chloropthalic acid the main the skeleton in the molecule is benzene ring.

In benzoic acid the one more carboxylic group is present at ortho position and one chloro group is present at para position of the ring.

The structure of the 4-chloropthalic acid is given in an image.

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0.24J/g*degC * 4.37g * 2.5degC = 2.622J

The 2.5 degC is the difference between 25 and 27.5 deg C.

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3 years ago
In science what can only be separated by Chemical methods​
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A mixture is a physical combination of substances thus it only requires physical processes to separate.

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What is the name of the molecule that is used to heat most of our buildings?<br><br> (Chemistry)
mario62 [17]

Answer:

Fluids (air/water) either as water vapour or oxygen and carbon dioxide.

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7 0
2 years ago
Does anybody know how to do q4. Please show working out thanks.
insens350 [35]

Answer:

% purity of limestone = 96.53%

Explanation:

Question (4).

Weight of impure CaCO₃ = 25.9 g

Molecular weight of CaCO₃ = 40 + 12 + 3(16)

                                              = 100 g per mole

We know at S.T.P. number of moles of CO₂ = 1 and volume = 22.4 liters

From the given reaction, 1 mole of CaCO₃ reacts with 1 mole or 22.4 liters of

CO₂.

∵ 22.4 liters of CO₂ was produced from CaCO3 = 100 g

∴ 1 liter of CO₂ will be produced by CaCO₃ = \frac{100}{22.4}

∴ 5.6 liters of CO₂ will be produced by CaCO₃ = \frac{100\times 5.6}{22.4}

                                                                              = 25 g

Therefore, % purity of CaCO₃ = \frac{\text{Weight calculated}}{{\text{Weight given}}}\times 100

                                                 = \frac{25}{25.9}\times 100

                                                 = 96.53 %

7 0
3 years ago
A student adds a rectangular block of mass 26.10 g to a graduated cylinder initially filled with 40.1 mL of water, but some wate
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The splash cause the volume of the block to be too high

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This is because, from the previous measurement made by the student, the volume of the block is 5.7ml higher.

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