Answer:
1- For the track B. The potential energy is the same for the two cars, but because of the slope of the track, the car B earn kinetic energy faster. The gravitation acceleration of the cars will be g•sinθ, and the angle of the track B will have a bigger value for sinθ
2- The conservation of energy applies because the roller coaster is a closed track. When a car climb the track, it earn GPE, which is given by mgh, when it get down in the track, it transform GPE in KE, which is given in 1/2mv².
3-
Position of car (m) GPE KE GPE + KE
top (30m) 60000 0 60000
bottom (0m) 0 60000 60000
halfway down (15m) 30000 30000 60000
three-quarters way down 15000 45000 60000
Answer:
well at the rate he goes he would be at 2.5km
Answer:
1. Flexibility.
2. Muscular Fitness
3. Cardiovascular Fitness
4. Cardiovascular Fitness
5. Flexibility
6. Muscular Fitness
7. Cardiovascular Fitness
Answer:
Explanation:
Let v be the terminal velocity of the bar .
emf induced in the bar of length L
= B L v where B is the value of magnetic field.
current i in the circuit containing resistance R
i = induced emf / R
BLv / R
Magnetic force in upward direction in the bar
F = BiL
= BL x BLv / R
B²L²v / R
For attainment of uniform velocity
magnetic force = weight
B²L²v / R = mg
so current
i = BLv / R