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klasskru [66]
3 years ago
7

1.D 2.A 3.A 4.im not sure please help 5.false One light bulb in a string of lights goes out. This causes all of the other lights

in the string to also go out. This is an example of a
A. resistor. B. parallel circuit. C. closed circuit. D. series circuit. 2.When a switch is turned from the off to the on position, it is changing the circuit in which of the following ways?
A. An open circuit is being changed into a closed circuit.
B. A closed circuit is being changed into an open circuit.
C. A parallel circuit is being changed into a series circuit.
D. A series circuit is being changed into a parallel circuit.
3.Early telephone poles had wires that connected inside bell-shaped glass enclosures like the ones shown below.
several bell-shaped glass enclosures These glass enclosures helped to keep the electric current from moving outside the circuit of wires. The glass enclosures were used as
A. insulators. B. conductors. C. resistors. D. switches. 4.Use Ohm’s Law to determine the resistance in a circuit if the voltage is 12.0 volts and the current is 4.0 amps.
A. 8.0 ohms B. 48 ohms C. 3.0 ohms D. 12 ohms 5.In a closed circuit, the current only flows from the power source to an electrical device such as a lamp
A.TRUE B.FALSE
Physics
1 answer:
Amiraneli [1.4K]3 years ago
6 0
Welll ... if you read the question, you'll see what a jumbled mess you actually
posted, but I think I can pull enough out of it to give you some answers.

<span>One light bulb in a string of lights goes out. This causes all of the
other lights in the string to also go out. The entire string of lights
must be one series circuit.

2.  When a switch is turned from the off to the on position,
an open circuit is changed to a closed circuit.

3.Early telephone poles had wires that connected inside bell-shaped
glass enclosures like the ones shown below.  (nothing is shown below)
several bell-shaped glass enclosures
These glass enclosures helped to keep the electric current from moving
outside the circuit of wires. The glass enclosures were used as insulators.

4.Use Ohm’s Law to determine the resistance in a circuit if the
voltage is 12.0 volts and the current is 4.0 amps.

Ohms law:        Resistance = (voltage) / (current)

                                             = (12.0 v) / (4.0 amp)

                                             =      3 ohms .

5.  "In a closed circuit, the current only flows from the power source
to an electrical device such as a lamp."

This statement is false.  The current eventually has to get back
to the power source.  If it doesn't then there's no 'circuit', and
nothing works.  That's a big part of the reason why the plug
has 2 prongs on it, and the cord from the plug to the lamp
has 2 wires in it. </span>
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A 0.500 kg bullet is fired from a gun at 25.0 m/s, how much kinetic energy does it have?
slamgirl [31]

Considering the definition of kinetic energy, the bullet has a kinetic energy of 156.25 J.

<h3>Kinetic energy</h3>

Kinetic energy is a form of energy. It is defined as the energy associated with bodies that are in motion and this energy depends on the mass and speed of the body.

Kinetic energy is defined as the amount of work necessary to accelerate a body of a given mass and in a rest position, until it reaches a given speed. Once this point is reached, the amount of accumulated kinetic energy will remain the same unless there is a change in speed or the body returns to its rest state by applying a force to it.

The kinetic energy is represented by the following expression:

Ec= ½ mv²

Where:

  • Ec is the kinetic energy, which is measured in Joules (J).
  • m is the mass measured in kilograms (kg).
  • v is the speed measured in meters over seconds (m/s).

<h3>Kinetic energy of a bullet</h3>

In this case, you know:

  • m= 0.500 kg
  • v= 25 m/s

Replacing in the definition of kinetic energy:

Ec= ½ ×0.500 kg× (25 m/s)²

Solving:

<u><em>Ec= 156.25 J</em></u>

Finally, the bullet has a kinetic energy of 156.25 J.

Learn more about kinetic energy:

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The force of attraction between any two objects is known as
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7 0
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A child on a swing sweeps out a distance of 45 ft on the first pass. If she is allowed to continue swinging until she​ stops, an
earnstyle [38]

Answer:

d = 90 ft

Explanation:

Here in each swing the distance sweeps by the swing is half of the initial distance that it will move

So here we can say that total distance in whole motion is  given as

d = 45 + \frac{45}{2} + \frac{45}{4} + \frac{45}{8}..........

since it is half of the distance that it will move in each swing so it would be a geometric progression with common ratio of 1/2

so sum of such GP is given by the formula

S = \frac{a}{1 - r}

d = \frac{45}{1 - \frac{1}{2}}

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∆H = 430 J

Explanation:

If asked for the value of ∆H the answer is simply the change in heat, and in the question, it states introduction of 430 J of heat is causing the system to expand.

Therefore ∆H = 430 J

If asked for ∆E, we know that ∆E = ±q (heat) + work (-P∆V) = ±q + w

The question states that 238 J of work are done AND the system expanded

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