A string is wound tightly around a fixed pulley having a radius of 5.0 cm. as the string is pulled, the pulley rotates without a
2 answers:
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is the acceleration of the box.
<u>Explanation:</u>
Given data:
Mass of the box = 3.74 kg
Flat friction-less ground is pulled forward by a 4.20 N force at a 50.0 degree angle and pulled back by a 2.25 N force at a 122 degree angle.
First, we need to find the net horizontal force acting on the box. With the given data, the equation can be formed as below. Net horizontal force acting on the box (F) is given by
F = 2.699676 – 1.192275 = 1.507 N
Next, find acceleration of the box using Newton's second law of motion. This states that the link between mass (m) of an objects and the force (F) required to accelerate it. The equation can be given as
If an object is given an initial velocity in any direction and then allowed to travel freely under gravity only, it is called a projectile motion.
It is basically 3 types
- horizontally projectile motion
- oblique projectile motion
- included plane projectile motion
The path followed by a projectile is called its trajectory.