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olasank [31]
3 years ago
8

Okay please help me all my assignments are due tomorrow! I need to know 5 examples of all 6 simple machines that can be found in

a house! Please specify the machine for the items! Thank you!
Physics
1 answer:
iren [92.7K]3 years ago
3 0

Answer:

Inclined Plane – A ramp, for example a wheelchair ramp. Paired inclined planes make a pitched roof.

Wheel & Axle – On lawnmowers and wheelbarrow. Also, found in cabinet door glides and on appliances. Another common example – door knobs and even inside those locksets.

Lever – The bottle opener. Tools – the crowbar, and scissors or pliers. Double Levers – a door, a toilet seat, a broom.

Pulley – Old wood windows, some garage doors, workshop or garage lifting systems.

Wedge – The shim – used throughout the home in construction. For example, when installing doors, windows, cabinets, etc. Sometimes used to level furniture or chairs.

Screw – Like the wedge, above, well, you couldn’t build a house without screws. Certain types of plumbing valves. Plus, a jar lid is a popular example.

Now for deeper look at the simple machines found around our homes.

The hope this will be helpful.

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X=(150^2•sin(2•42))/9.8
amid [387]

Answer:

2283.3410863

Explanation:

3 0
3 years ago
Read 2 more answers
When atoms of an element are excited, they emit specific wavelengths of light. How is this similar to a fingerprint when Fraunho
Anika [276]

Answer:

As you may know, each element has a "fixed" number of protons and electrons.

These electrons live in elliptical orbits around the nucleus, called valence levels or energy levels.

We know that as further away are the orbits from the nucleus, the more energy has the electrons in it. (And those energies are fixed)

Now, when an electron jumps from a level to another, there is also a jump in energy, and that jump depends only on the levels, then the jump in energy is fixed.

Particularly, when an electron jumps from a more energetic level to a less energetic one, that change in energy must be compensated in some way, and that way is by radiating a photon whose energy is exactly the same as the energy of the jump.

And the energy of a photon is related to the wavelength of the photon, then we can conclude that for a given element, the possible jumps of energy levels are known, meaning that the possible "jumps in energy" are known, which means that the wavelengths of the radiated photons also are known. Then by looking at the colors of the bands (whose depend on the wavelength of the radiated photons) we can know almost exactly what elements are radiating them.

7 0
3 years ago
Calculate the wavelength of each frequency of electromagnetic radiation: a. 100.2 MHz (typical frequency for FM radio broadcasti
Natalka [10]

Answer:

a). 100.2 MHz (typical frequency for FM radio broadcasting)

The wavelength of a frequency of 100.2 Mhz is 2.99m.

b. 1070 kHz (typical frequency for AM radio broadcasting) (assume four significant figures)

The wavelength of a frequency of 1070 khz is 280.3 m.

c. 835.6 MHz (common frequency used for cell phone communication)

The wavelength of a frequency of 835.6 Mhz is 0.35m.

Explanation:

The wavelength can be determined by the following equation:

c = \lambda \cdot \nu  (1)

Where c is the speed of light, \lambda is the wavelength and \nu is the frequency.  

Notice that since it is electromagnetic radiation, equation 1 can be used. Remember that light propagates in the form of an electromagnetic wave.

<em>a). 100.2 MHz (typical frequency for FM radio broadcasting)</em>

Then, \lambda can be isolated from equation 1:

\lambda = \frac{c}{\nu} (2)

since the value of c is 3x10^{8}m/s. It is necessary to express the frequency in units of hertz.

\nu = 100.2 MHz . \frac{1x10^{6}Hz}{1MHz} ⇒ 100200000Hz

But 1Hz = s^{-1}

\nu = 100200000s^{-1}

Finally, equation 2 can be used:

\lambda = \frac{3x10^{8}m/s}{100200000s^{-1}}

\lambda = 2.99 m

Hence, the wavelength of a frequency of 100.2 Mhz is 2.99m.

<em>b. 1070 kHz (typical frequency for AM radio broadcasting) (assume four significant figures)</em>

<em> </em>

\nu = 1070kHz . \frac{1000Hz}{1kHz} ⇒ 1070000Hz

But  1Hz = s^{-1}

\nu = 1070000s^{-1}

Finally, equation 2 can be used:

\lambda = \frac{3x10^{8}m/s}{1070000s^{-1}}

\lambda = 280.3 m

Hence, the wavelength of a frequency of 1070 khz is 280.3 m.

<em>c. 835.6 MHz (common frequency used for cell phone communication) </em>

\nu = 835.6MHz . \frac{1x10^{6}Hz}{1MHz} ⇒ 835600000Hz

But  1Hz = s^{-1}

\nu = 835600000s^{-1}

Finally, equation 2 can be used:

\lambda = \frac{3x10^{8}m/s}{835600000s^{-1}}

\lambda = 0.35 m

Hence, the wavelength of a frequency of 835.6 Mhz is 0.35m.

6 0
3 years ago
A wave travels at a frequency of 387 Hz. What is<br>the period of the wave?<br>​
Ulleksa [173]

Answer:

¹/₃₈₇ second

Explanation:

<em>The period of a wave is the reciprocal of its frequency.</em>

So, simply, the frequency is ¹/₃₈₇ second(s), as that is the reciprocal of the frequency, 387 Hz.

5 0
4 years ago
You are approaching a police car at 68. 1 mph and the police car is approaching you at 94. 8 mph. Assume that the speed of sound
Veronika [31]

We will hear the sound of siren of frequency 1553.4606 Hz.

<h3>What is Doppler Effect?</h3>

The apparent change in wave frequency brought on by the movement of a wave source is known as the Doppler effect. When the wave source is coming closer and when it is moving away, the perceived frequency changes. The Doppler effect explains why we hear a passing siren's sound changing in pitch.

according to Dopplers Effect,

f'=[\frac{v + v_{0} }{v - v_{s} } ]f

f'= [\frac{700+68.1}{700-94.8} ]* 1224

f'= 1553.4606 Hz

the frequency would be 1553.4606 Hz.

to learn more about Doppler Effect go to - brainly.com/question/9165991

#SPJ4

7 0
2 years ago
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