Answer:
It's due to the distance from either ends of strings origin...
Explanation:
As we know that waves behave moving in a flow from one side to another side and this gives a prospective of motion. Suppose a wave is pinched from the near one end of a guitar then due to the distortion created by the point of tie of strings the wave super imposes and moves with a velocity v and produces a wave frequency f. as we the pinching go down to the center the wave stabilizes itself to a stationary origin right at the center and the frequency then changes accordingly as moving down on the string.
Answer:489 Revolutions
Explanation:
Given
Angular deceleration
Given wheel angular velocity =96 rad/s when machine is turned off
time taken by machine to reach zero angular velocity
0=96+(-1.5)t
t=64 sec
angular displacement is given by
For revolutions =
Might help:
an object can have both kinetic and potential energy at the same time. for example, an object which is falling, but has not reached the ground has kinetic energy because it is moving downwards, and potential energy because it is able to move downwards even further than it already has. as an object falls its potential energy decreases, while its kinetic energy increases. the decrease in potential energy is exactly equal to the increase in kinetic energy.
Answer:
A) The time of the observer on the surface of the mars is the proper time.
B) Duration = 434.65 μs
Explanation:
A) From the question, we see that the signal light blinked on the Martian surface which is the same frame of reference of the observer at rest. Hence, we can say that the time of the observer on mars is the proper time.
B) time dilation equation is given as;
Δt =γ•Δt(o)
Where Δt is the duration of the light pulse measured by the pilot of the spaceship.
γ = 1/(√(1-β²))
Now,
β is expressed as β = u/c
Thus;
γ = 1/(√(1-(u/c)²)) = 1/(√(1-(u²/c²)))
Where, u is the speed of the spaceship relative to the surface of planet mars.
From the question, u = 0.985c
Thus, plugging in the relevant values, we obtain;
Δt = [1/(√(1-(0.985²c²/c²))] x 75
Δt = [1/(√(1-(0.985²))] x 75 = [1/(√(0.029775)]75= 5.7953 x 75 =
434.65μs
