This sequence refer to how neurons send messages electrochemically. When the neurons are at rest, they are at its resting potential at -70 millivolts. If the neurons in the brain send messages, a spike would occur until it reaches the threshold potential at -55 mV. If it reaches the threshold potential, then an action potential occurs.Hence, the sequence would be letter C.
Answer:
because the dog cat moster ate a bean. the answer is 68
Explanation:
Answer:
you cant really give any answers because i cant tell u were to drag
Answer:
(a) 42 N
(b)36.7 N
Explanation:
Nomenclature
F= force test line (N)
W : fish weight (N)
Problem development
(a) Calculating of weight of the heaviest fish that can be pulled up vertically, when the line is reeled in at constant speed
We apply Newton's first law of equlibrio because the system moves at constant speed:
∑Fy =0
F-W= 0
42N -W =0
W = 42N
(b) Calculating of weight of the heaviest fish that can be pulled up vertically, when the line is reeled with an acceleration whose magnitude is 1.41 m/s²
We apply Newton's second law because the system moves at constant acceleration:
m= W/g , m= W/9.8 , m:fish mass , W: fish weight g:acceleration due to gravity
∑Fy =m*a
m= W/g , m= W/9.8 , m:fish mass , W: fish weight g:acceleration due to gravity
F-W= ( W/9.8 )*a
42-W= ( W/9.8 )*1.41
42= W+0.1439W
42=1.1439W
W= 42/1.1439
W= 36.7 N
Answer:
The density of the woman is 950.8 kg/m³
Explanation:
Given;
fraction of the woman's volume above the surface = 4.92%
then, fraction of the woman's volume below the surface = 100 - 4.92% = 95.08%
the specific gravity of the woman ![= \frac{95.08}{100 } = 0.9508](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B95.08%7D%7B100%20%7D%20%3D%200.9508)
The density of the woman is calculate as;
![Specific \ gravity \ of \ the \ woman = \frac{Density \ of \ the \ woman }{Density \ of \ fresh \ water }\\\\ Density \ of \ the \ woman = Specific \ gravity \ of \ the \ woman \ \times \ Density \ of \ fresh \ water](https://tex.z-dn.net/?f=Specific%20%5C%20gravity%20%5C%20of%20%5C%20the%20%5C%20woman%20%3D%20%5Cfrac%7BDensity%20%5C%20of%20%5C%20the%20%5C%20woman%20%7D%7BDensity%20%5C%20of%20%5C%20fresh%20%5C%20water%20%7D%5C%5C%5C%5C%20Density%20%5C%20of%20%5C%20the%20%5C%20woman%20%20%3D%20Specific%20%5C%20gravity%20%5C%20of%20%5C%20the%20%5C%20woman%20%5C%20%5Ctimes%20%5C%20Density%20%5C%20of%20%5C%20fresh%20%5C%20water)
Density of fresh water = 1000 kg/m³
Density of the woman = 0.9508 x 1000 kg/m³
Density of the woman = 950.8 kg/m³
Therefore, the density of the woman is 950.8 kg/m³