#1). First of all, the 220 volts has to be changed to something near 110 volts. The most convenient way to do that is with a 2:1 step-down transformer. Those are readily available, for exactly this purpose, in kits of "travelers' accessories".
#2). Since Steve's immediate concern is his alarm clock, there's another important detail that he needs to consider. The power from the electrical outlets in the US is supplied at 60Hz, whereas the power in most of the rest of the world comes out at 50Hz. Many clocks use the frequency of the power outlet to keep time. If his 110V alarm clock is one of those and is designed for 60Hz, then if it's run on 50Hz power, it'll lose 10minutes of time every hour !
Steve's easiest and most economical solution might simply be to buy an alarm clock when he lands in New Zealand.
I think the answer is “greenhouse effect”
Because the masses that you give are for blocks that are 1 cubic meter in volume, they also serve as the densities for the two metals that you are comparing.
<span>mass = density*volume </span>
<span>volume = (4/3)*pi*r^3 </span>
<span>volume of iron sphere = (4/3)*3.14*0.0201^3 = 3.40*10^-5 m^3 </span>
<span>mass of iron sphere = 7860* 3.40*10^-5 m^3 = 0.27 kg = mass of Aluminum Sphere </span>
<span>Volume of Al Sphere = 0.27/2700 = 9.90*10^-5 m^3 </span>
<span>Radius = cube root (volume / (4/3) / pi) = 2.87 cm. </span>
<span>I did this using the MS calculator, and I'm not 100% sure on the numerical answer, but the process is what you need to do to solve the problem. You should double check my answer.
hope this helped :)
</span>
Answer:
480.2 m
Explanation:
The following data were obtained from the question:
Speed of sound (v) = 343 m/s.
Time (t) = 2.8 s
Distance (x) of the cliff =?
The distance of the cliff from the woman can be obtained as follow:
v = 2x /t
343 = 2x /2.8
Cross multiply
2x = 343 × 2.8
2x = 960.4
Divide both side by the coefficient of x i.e 2
x = 960.4/2
x = 480.2 m
Therefore, the cliff is 480.2 m away from the woman.
Answer:
The correct option is C: 0.31 s.
Explanation:
When the mass is then suddenly released we have:
Where:
F is the force
k: is the spring constant
Δy: is the spring displacement
Since the tension in the spring is zero, the force is the weight:
Where:
m is the mass of the object
g is the gravity
(1)
The oscillation period of the spring is given by:
(2)
By solving equation (1) for "k" and entering into equation (2) we have:
Since the spring will osclliates in a position between the initial position (when it is at rest) and the final position (when the mass is released and reaches the bottom), we have Δy = 2.5 cm = 0.025 m:
Hence, the oscillation period is 0.31 s.
The correct option is C: 0.31s.
I hope it helps you!
