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8_murik_8 [283]
4 years ago
8

ASAP pls answer right if can’t see picture don’t answer

Physics
1 answer:
Anna35 [415]4 years ago
6 0

Answer:

Not sure but

F = m* a

32= 5 * a

a= 6.4 m/s^2

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True or False <br> Most magnets are made<br> from 100% aluminum
bazaltina [42]

Answer:

True

I hope it helps.

4 0
3 years ago
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In an arcade game a 0.135 kg disk is shot across a frictionless horizontal surface by compressing it against a spring and releas
ioda

Answer:

v=2.42m/s

Explanation:

We use the energy conservation theorem in order to solve the problem. The energy when the spring is compressed is equal at the energy when the disk leaves the spring:

E_{initial}=E{final}\\E_{k-initial}+E_{p-initial}=E_{k-final}+E_{p-final}\\0+\frac{1}{2}kx^2=\frac{1}{2}mv^2+0

At the beginning the initial energy is totally potential, energy linked to the compressed spring. At the end the energy is totally kinetics

We solve the equation in order to find the speed.

k=162 N/m

x=7 cm=0.07m

m=0.135 kg

v=x*\sqrt{k/m}=0.07*\sqrt{162/0.135}=2.42m/s

6 0
3 years ago
Robert, a stuntman, projects himself from a height of 50.0 meters in a horizontal direction. He safely lands at a horizontal dis
Olin [163]
To get this we need to know how long he was traveling. To know that we need to solve for the time it took for him to hit the ground. This is given by the vertical height he started at and the equation of motion for falling objects. The position function is
Y= -(9.8/2)t^2 + 50 = 0
t=3.19s
That's how long he's in the air. When he hits the ground he stops moving forward so this is also the amount of time he was moving at 100m/s horizontally. Now use speed distance relationship
X=vt
And solve for v
100m/3.19s = 31.35m/s
3 0
4 years ago
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A hockey puck sliding at 60.0m/s slows uniformly to 20.0m/s while travelling 800.0m.
julia-pushkina [17]
A) -3.75 meters/second
A=(20^2-80^2)/(2x800)
=(400-6400)/1600
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=-3.75
B) 16 seconds
t=(20-80)/-3.75
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3 0
3 years ago
A circular loop of flexible iron wire has an initial circumference of 165.0cm, but its circumference is decreasing at a constant
djverab [1.8K]

Answer:

0.005 V

Explanation:

We are given that

Initial circumference of circular loop=C=165 cm

Rate of circumference,\frac{dC}{dt}=12 cm/s

Magnetic field,B=0.5 T

We have to find the induced emf at time t=9 s

We know that induced amf,E=\frac{Bd(A)}{dt}

Area of circular coil,A=\pi r^2

E=B\frac{d(\pi r^2)}{dt}=B(2\pi r)\frac{dr}{dt}

Circumference of circular coil,C=2\pi r

165=2\pi r

r=\frac{165}{2\pi}

\frac{dr}{dt}=\frac{1}{2\pi}\frac{dC}{dt}=\frac{1}{2\pi}\times (12)=\frac{6}{\pi} cm/s=\frac{6\times 10^{-2}}{\pi} m/s

Radius of coil at time t=9 s

r=\frac{165}{2\pi}-(\frac{6}{\pi}\times 9)=9.08 cm=9.08\times 10^{-2} m

1 m=100 cm

E=-0.5(2\pi\times 9.08\times 10^{-2})\times \frac{6\times 10^{-2}}{\pi}=-0.005 V

Magnitude of induced emf=0.005 V

4 0
3 years ago
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