When the initial speed given is 7.5m/s at an angle of 27° , ball will go
4.637 meters.
Assume no air opposition to the ball ;
Vertical component of ball is sin 27° = 0.453
0.453* 7.5 = 3.404 meters /sec
Time taken to reach ground is :
3.404 = -3.404+9.8*t
t= 6.808/9.8= 0.694 sec
Horizontal component is 7.5*cos27°= 6.682m/s
Distance = speed * time
=6.682 * 0.694
=4.637 meters
Horizontal distance it can cover in 0.694 sec is 4.637 meters
So range of ball is 4.637 meters.
Form of motion experienced by an object or particle that is projected near surface of the earth and moves along a curve is called Projectile motion. Three types of projectile motion are Horizontal projectile motion. Oblique projectile motion and Projectile motion on an inclined plane.
To know more about projectile motion, refer
brainly.com/question/24216590
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All matter is composed of atoms, indestructible building blocks.
So what u do is 2112393921010
Answer:
T1 = T2 = 602.33 N
Explanation:
I attached an image of the forces diagram below.
The x component of the forces for this cases is:

And the y components:

The angle is calculated by using the information about the length of the cable and the vertical distance of the traffic light:

Thus, you obtain:

hence, the tension in both segments of the cable is 602.33 N