2 years ago

Which is the atomic number of the carbon diagram below!

Physics

1 answer:

san4es73 [151]2 years ago

8 0

Answer: 6

Explanation: the number that is in the corner is always the atomic number.

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How do magnet effect materials that are not magnets

givi [52]

Answer: Magnetic metals & non-magnetic metals both play an important role in engineering. Magnetism is the basis for many applications. At the same time, this property may also be unwanted in certain circumstances.

Therefore, it is important to know which metals are magnetic and which ones are not.

Explanation:

3 0

2 years ago

The magnetic circuit below is excited by a 100-turn coil wound over the central leg. The mean length of the central leg is 5.5cm

Dafna11 [192]

Answer:

Hello your question is incomplete attached below is the complete question and solution

answer;

attached below

Explanation:

Given data:

100-turn coil

mean length of central leg = 5.5 cm

mean length of outer paths = 15.5 cm

relative permeability = 2000

cross sectional area ( A ) = 1 cm^2

distance x = 1 cm

attached below is a detailed solution

3 0

2 years ago

Joaquin is at rest at the top of a hill on a skateboard. Four seconds later, he reaches the bottom of the hill at a final veloci

Andre45 [30]

Explanation:

Given: Initial Velocity=0

Final Velocity= 20 m/s

Time= 4 s

Accleration: Unknowns

Use kinematic equation

$v _{f} = v _{i} + at$

$20 = 0 + at$

$\frac{20m}{s} = a(4s)$

$a = \frac{5m}{ {s}^{2} }$

so a = 5 m/s^2

8 0

2 years ago

If X = 5 and Y = 3, what does Z equal? 2X + 2Z = 10Y

Margarita [4]

2(5) + 2 (z) = 10{3}
10 + 2z= 30
2z=20
z=10

4 0

3 years ago

Read 2 more answers

One end of a rope is tied to the handle of a horizontally-oriented and uniform door. a force f is applied to the other end of th

Vlada [557]

For rotational equilibrium of the door we can say that torque due to weight of the door must be counter balanced by the torque of external force

$F\times L = mg \times \frac{L}{2}$

here weight will act at mid point of door so its distance is half of the total distance where force is applied

here we know that

$mg = 145 N$

now we will have

$F = \frac{mg}{2}$

$F = \frac{145}{2} = 72.5 N$

so our applied force is 72.5 N

7 0

3 years ago