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4 years ago

15

Welded or riveted fuel tanks may be sealed by pouring a liquid sealant into the tank and allowing it to cover the entire inside

of the tank. The surplus is poured out, and that which remains is allowed to cure. This method of sealing is called ____ the tank.

1 answer:

zimovet [89]4 years ago

6 0

Answer:

Sloshing

Explanation:

Because in this method as explained above Welded or riveted fuel tanks may be sealed by pouring a liquid sealant into the tank and allowing it to cover the entire inside of the tank. The surplus is poured out, and that which remains is allowed to cure.

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4 years ago

To understand the decibel scale. The decibel scale is a logarithmic scale for measuring the sound intensity level. Because the d

frez [133]

The question is incomplete. Here is the complete question.

To understand the decibel scale. The decibel scale is a logarithmic scale for measuring the sound intensity level. Because the decibel scale is logarithmic, it changes by an additive constant when the intensity when the intensity as measured in W/m² changes by a multiplicative factor. The number of decibels increase by 10 for a factor of 10 increase in intensity. The general formula for the sound intensity level, in decibels, corresponding to intensity I is

$\beta=10log(\frac{I}{I_{0}} )dB$ ,

where $I_{0}$ is a reference intensity. for sound waves, $I_{0}$ is taken to be $10^{-12} W/m^{2}$ . Note that log refers to the logarithm to the base 10.

Part A: What is the sound intensity level β, in decibels, of a sound wave whose intensity is 10 times the reference intensity, i.e. $I=10I_{0}$ ? Express the sound intensity numerically to the nearest integer.

Part B: What is the sound intensity level β, in decibels, of a sound wave whose intensity is 100 times the reference intensity, i.e. $I=100I_{0}$ ? Express the sound intensity numerically to the nearest integer.

Part C: Calculate the change in decibels ( $\Delta \beta_{2},\Delta \beta_{4}$ and $\Delta \beta_{8}$ ) corresponding to f = 2, f = 4 and f = 8. Give your answer, separated by commas, to the nearest integer -- this will give an accuracy of 20%, which is good enough for sound.

Answer and Explanation: Using the formula for sound intensity level:

A) $I=10I_{0}$

$\beta=10log(\frac{10I_{0}}{I_{0}} )$

$\beta=10log(10 )$

β = 10

<u>The sound Intensity level with intensity 10x is </u><u>10dB</u>.

B) $I=100I_{0}$

$\beta=10log(\frac{100I_{0}}{I_{0}} )$

$\beta=10log(100)$

β = 20

<u>With intensity 100x, level is </u><u>20dB</u>.

C) To calculate the change, take the f to be the factor of increase:

For $\Delta \beta_{2}$ :

$I=2I_{0}$

$\beta=10log(\frac{2I_{0}}{I_{0}} )$

$\beta=10log(2)$

β = 3

For $\Delta \beta_{4}$ :

$I=4I_{0}$

$\beta=10log(\frac{4I_{0}}{I_{0}} )$

$\beta=10log(4)$

β = 6

For $\Delta \beta_{8}$ :

$I=8I_{0}$

$\beta=10log(\frac{8I_{0}}{I_{0}} )$

β = 9

Change is

$\Delta \beta_{2},\Delta \beta_{4}$ , $\Delta \beta_{8}$ = 3,6,9 dB

6 0

3 years ago

The demand equation for the Roland portable hairdryer is given as follows where x (measured in units of a hundred) is the quanti

lesya [120]

Answer:

Explanation:

The concept of elastic and inelastic demand is applied.

for an elastic demand, the elasticity must be greater than 1 and for an Inelastic demand, the elasticity must be less than 1.

The steps and appropriate calculation is as shown in the attached file.

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4 years ago

Nitroball is similar to volleyball with no more than 3 touches per side?

ankoles [38]

Answer:

True!

Explanation:

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3 years ago

if charge is located at center of spherical volume and electric flux through surface of sphere is Φ what would be flux through s

jonny [76]

Answer:

The flux will be nine times as great.

Explanation:

The electric flux due to a charge Q located in the center of a sphere can be obtained using Gauss's law. Considering a Gaussian surface in the form of a sphere of radius r:

$\Phi_E=\int\limits {Ecos\theta dS} \,$

The electric field (E) is parallel to the surface vector (dS), so $\theta=0$

$\Phi_E=\int\limits{Ecos(0)dS} \,\\\Phi_E=E\int\limits{dS} \,\\\Phi_E=ES\\\Phi_E=E4\pi r^2$

Since the electric flux is proportional to the square of the sphere's radius, if radius of sphere were tripled, the flux will be nine times as great.

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3 years ago