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klio [65]
3 years ago
13

According to the principle of original horizontality what most likely happened to the rock layers in the background ?

Chemistry
2 answers:
bulgar [2K]3 years ago
7 0

Answer:

D. They were deposited horizontally and then shifted by a geologic event.

Explanation: The only one that explains horizontally.

Lapatulllka [165]3 years ago
5 0

The principle of original horizontality states that all rock layers were initially deposited horizontally.  The answer must be They were deposited horizontally and then shifted by a geologic event because they other choices all indicate that the the rocks were initially deposited in a way that was not horizontal.


Hope this helps!!

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The cell potential of a redox reaction occurring in an electrochemical cell under any set of temperature and concentration condi
avanturin [10]

Answer : The actual cell potential of the cell is 0.47 V

Explanation:

Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given redox reaction is :

Ni^{2+}(aq)+Zn(s)\rightarrow Ni(s)+Zn^{2+}(aq)

The balanced two-half reactions will be,

Oxidation half reaction : Zn\rightarrow Zn^{2+}+2e^-

Reduction half reaction : Ni^{2+}+2e^-\rightarrow Ni

The expression for reaction quotient will be :

Q=\frac{[Zn^{2+}]}{[Ni^{2+}]}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

Q=\frac{(0.0141)}{(0.00104)}=13.6

The value of the reaction quotient, Q, for the cell is, 13.6

Now we have to calculate the actual cell potential of the cell.

Using Nernst equation :

E_{cell}=E^o_{cell}-\frac{RT}{nF}\ln Q

where,

F = Faraday constant = 96500 C

R = gas constant = 8.314 J/mol.K

T = room temperature = 316 K

n = number of electrons in oxidation-reduction reaction = 2 mole

E^o_{cell} = standard electrode potential of the cell = 0.51 V

E_{cell} = actual cell potential of the cell = ?

Q = reaction quotient = 13.6

Now put all the given values in the above equation, we get:

E_{cell}=0.51-\frac{(8.314)\times (316)}{2\times 96500}\ln (13.6)

E_{cell}=0.47V

Therefore, the actual cell potential of the cell is 0.47 V

4 0
3 years ago
What explains the relationship among elements, compounds & mixtures
Sauron [17]
Elements are like loners, compounds are like couples, and mixtures are like a group of friends that can also have couples (compounds)
3 0
3 years ago
Competition is rivalry between individuals for a particular resource.
djyliett [7]

Answer:

True

Explanation:

Competition is the act of competing with one another for a particular resource. An example is two animals quarrelling over a food or two people quarreling over who lost their money. Competing is a type of rivalry in which two people compete for one resource. The answer for this question is True.

5 0
3 years ago
Read 2 more answers
How many molecules of CO 2 are equivalent to 112 g CO 2 ?
Westkost [7]

Answer:

Explanation:

CO2=1.53x10^2

6 0
3 years ago
Read 2 more answers
Please help no links
jarptica [38.1K]

Answer:

23 L

Explanation:

We'll begin by converting celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 100 °C

Initial temperature (T₁) = 100 °C + 273

Initial temperature (T₁) = 373 K

Final temperature (T₂) = 50.5 °C

Final temperature (T₂) = 50.5 °C + 273

Final temperature (T₂) = 323.5 K

Finally, we shall determine the initial volume of gas. This can be obtained as follow:

Initial temperature (T₁) = 373 K

Final temperature (T₂) = 323.5 K

Final volume (V₂) = 20 L

Initial volume (V₁) =?

V₁/T₁ = V₂/T₂

V₁ / 373 = 20 / 323.5

Cross multiply

V₁ × 323.5 = 373 × 20

V₁ × 323.5 = 7460

Divide both side by 323.5

V₁ = 7460 / 323.5

V₁ = 23 L

Thus, the original volume of the gas is 23 L

7 0
2 years ago
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