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3 years ago

Which statement is true concerning the elements in families 1 and 2?

Chemistry

1 answer:

jeka57 [31]3 years ago

5 0

Answer:

The correct option is;

D. All the elements in families 1 and 2 can place all their shell electrons in the s sub-level

Explanation:

The elements in families 1 and 2 also called the group 1A and group 2A elements are known as the alkali and alkaline earth metals. The elements in the families 1 and 2 are also referred to as the s-block elements as they have their valence electrons which are 1 and 2 respectively, in the s-orbital or s sub-level

Due to their low ionization energy, and the ease with which they donate their valence electrons, elements of the families 1 and 2 are known to be very reactive, and are found in a combined state in nature.

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The neighborhood swimming pool is 20 feet long, 8 feet wide, and 4 feet deep. Which formula below should be used to find how muc

tino4ka555 [31]

Answer:

The formula to use is

VOLUME=LENGTH×BREADTH×HEIGHT

PLEASE GIVE BRAINLIEST

3 0

3 years ago

Be sure to answer all parts. Plutonium−242 decays to uranium−238 by emission of an α particle with an energy of 4.853 MeV. The 2

zheka24 [161]

Answer:

(a)²⁴²₉₄Pu ⇒ ⁴₂He + ²³⁸₉₂U ⇒ ²³⁸₉₂U + ⁰₀γ

(b) 4.898 MeV

Explanation:

In the nuclear reaction, it was stated that plutonium-242 decayed firstly to uranium-238 and alpha, and lastly to a stable uranium-238 by emitting a gamma ray. The balanced equation for the nuclear reactions is shown below:

(a)²⁴²₉₄Pu ⇒ ⁴₂He + ²³⁸₉₂U ⇒ ²³⁸₉₂U + ⁰₀γ

(b) The energy emitted by releasing a gamma ray is calculated using:

E = hc/λ

where

h = 4.136*10^-15 eV.s

c = 299792458 m/s

λ = 0.02757 nm = 0.02757*10^-9 m

Therefore:

E = (4.136*10^-15)*(299792458)/0.02757*10^-9 = 44974.31 eV

The total energy if the stable 238U was produced directly would be

4.853*10^6 + 44974.31 = 4.898 MeV

4 0

4 years ago

What is an ecosystem?<br> living environment by the way

MAVERICK [17]

An ecosystem is a lot of things and places that need each other to survive

4 0

4 years ago

Enter the formula for the polyatomic ion in MnCO3.

joja [24]

The formula is Mn2+CO2= MnCO3

8 0

3 years ago

The following equation shows the equilibrium in an aqueous solution of ammonia: NH3(aq)+H2O(l)⇌NH4+(aq)+OH−(aq)NH3(aq)+H2O(l)⇌NH

yarga [219]

Answer:

c) H2O and OH−

Explanation:

Acids are the species which furnish hydrogen ions in the solution or is capable of forming bonds with electron pair species as they are electron deficient species.

When an acid donates a proton, it changes into a base which is known as its conjugate base.

Bases are the species which furnish hydroxide ions in the solution or is capable of forming bonds with electron deficient species as they are electron rich species. When a base accepts a proton, it changes into a acid which is known as its conjugate acid.

The acid and the base which is only differ by absence or presence of the proton are known as acid conjugate base pair.

Thus, for the reaction,

$NH_3+H_2O\rightleftharpoons Nh_4^++OH^-$

The base is $NH_3$ and the conjugate acid of the base is $NH_4^+$ .

Also, The base is $OH^-$ and the conjugate acid of the base is $H_2O$ .

<u>Correct option is :- c) H2O and OH−</u>

8 0

3 years ago