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notsponge [240]
3 years ago
7

What is the reaction rate at 1000 K K when the concentration of NO N O is increased to 0.12 M M , while the concentration of H2

H 2 is 2.00×10−2 M M ?
Chemistry
1 answer:
marissa [1.9K]3 years ago
4 0

Answer:

the reaction rate of 1,000 k is 17.28 m/s

Explanation:

The computation of the reaction rate in case when NO is increased to 0.12 M is shown below:

According to the question, data provided is as follows

NO = 0.12M

H_2 = 2.00\times 10^{-2} M

Based on the above information

Reaction rate is

= (6.0\times10^4)\times(0.12)^2\times(2\times10^{-2})

= 17.28 M/s

Hence, the reaction rate of 1,000 k is 17.28 m/s and the same is to be considered

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Is table salt a compound
Anna11 [10]

Answer:

Yes it is a compound

Explanation:

NaCl sodium and chlorine

4 0
3 years ago
Read 2 more answers
In an organic structure, you can classify each of the carbons as follows: Primary carbon (1o) = carbon bonded to just 1 other ca
Alla [95]

The question is incomplete, complete question is :

In an organic structure, you can classify each of the carbons as follows: Primary carbon (1°) = carbon bonded to just 1 other carbon group Secondary carbon (2°) = carbon bonded to 2 other carbon groups Tertiary carbon (3°) = carbon bonded to 3 other carbon groups Quaternary carbon (4°) = carbon bonded to 4 other carbon groups How many carbons of each classification are in the structure below? How many total carbons are in the structure? How many primary carbons are in the structure? How many secondary carbons are in the structure? How many tertiary carbons are in the structure? How many quaternary carbons are in the structure?

Structure is given in an image?

Answer:

There are 10 carbon atoms in the given structures out of which 6 are 1° , 1 is 2° , 2 are 3° and 1 is 4°.

Explanation:

Total numbers of carbon = 10

Number of primary carbons that is carbon joined to just single carbon atom = 6

Number of secondary carbons that is carbon joined to two carbon atoms = 1

Number of tertiary carbons that is carbon joined to three carbon atoms = 2

Number of quartenary carbons that is carbon joined to four carbon atoms = 1

So, there are 10 carbon atoms in the given structures out of which 6 are 1° , 1 is 2° , 2 are 3° and 1 is 4°.

3 0
3 years ago
Suppose 0.795 g of sodium iodide is dissolved in 100. mL of a 39.0 m M aqueous solution of silver nitrate.
lubasha [3.4K]

Answer:

The final molarity of iodide anion is 0.053 M

Explanation:

<u>Step 1</u>: Data given

Mass of sodium iodide (NaI) = 0.795 grams

Volume of the solution = 100 mL = 0.1 L

Molarity of aqueous solution of silver nitrate (AgNO3) = 39 mM = 0.039M

The molecular mass of sodium iodide is 149.89 g/mol.

<u>Step 2:</u> The balanced equation

AgNO3(aq) + NaI(aq) → AgI(s) + NaNO3(aq)

<u>Step 3: </u>Calculate number of moles of sodium iodide

Moles NaI = mass NaI / Molar mass NaI

Moles NaI = 0.795 grams / 149.89 g/mol

Moles NaI = 0.0053 moles

For 1 mole AgNO3 consumed, we need 1 mole NaI to produce 1 mole AgI and 1 mole NaNO3

The sodium iodide will dissociate as followed:

NaI(aq) → Na+(aq) +  I-(aq)

<u>Step 4</u>: Calculate iodide ions

For 1 mole NaI, we have 1 mole of I-

For 0.0053 moles of NaI we'll have 0.0053 moles I-

<u>Step 5:</u> Calculate molarity of iodide ion

Molarity = moles I- / volume

Molarity I- = 0.0053 moles / 0.1 L

Molarity I- = 0.053 M

The final molarity of iodide anion is 0.053 M

5 0
3 years ago
What is the specific heat of a substance if a mass of 10.0 kg increases in temperature from 10.0°c to 70.0°c when 2,520 j of hea
LekaFEV [45]

Answer:

0.00420

Explanation:

The equation is Q=mc(T(final)-T(initial), where c is the specific heat, Q is heat supplied, m is mass, T(final) is final temperature and T(initial) is initial temperature (you'll see this written as delta T, which means change in temperature).

2520 = Q

m = 10.0kg; answer choices are in g, not kg, so multiply by 1000 to get m in g; m = 10000 g

Plug in the values you have and solve for c.

2520=(10000)(c)(70-10)

2520=600000c

c=0.0042 j/(gc)

5 0
2 years ago
Read 2 more answers
If two students in a lab are asked to calculate the density of a block with a mass of 31.0 g; they are not told how many digits
Arada [10]

We can see here that the both measurements are accurate. This is the true because the both values are in the correct number of significant figures.

<h3>What is density?</h3>

The term density has to do with the ratio of the mass to the density of the object. We know that the accuracy of a measurement has a lot to do with the number of significant figures in the measurement. In this case, we are told that two students in a lab are asked to calculate the density of a block with a mass of 31.0 g; they are not told how many digits to round their measurements. Student A finds length to be 2 cm width to be 4 cm and height 8 cm. Student B finds the length to be 2.65 cm, width to be 4.20 cm, and height to be 8.35 cm.

For the first student, the density is obtained as;

Density = mass/ volume

= 31.0 g/ 2 cm * 4 cm *  8 cm

= 0.5 g/cm^3

For the second student;

Density = mass/ volume

= 31.0 g/2.65 cm * 4.20 cm * 8.35 cm

= 0.33 g/cm^3

Learn more about density:brainly.com/question/15164682

#SPJ1

3 0
1 year ago
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