Assume the snow is uniform, and horizontal.
Given:
coefficient of kinetic friction = 0.10 = muK
weight of sled = 48 N
weight of rider = 660 N
normal force on of sled with rider = 48+660 N = 708 N = N
Force required to maintain a uniform speed
= coefficient of kinetic friction * normal force
= muK * N
= 0.10 * 708 N
=70.8 N
Note: it takes more than 70.8 N to start the sled in motion, because static friction is in general greater than kinetic friction.
Answer:
11.6532 x 10⁻¹¹ J or 7.3 MeV is given off
Explanation:
Mass of an alpha particle = 4.0026u, ∴ mass of three = 12.0078u
Find the difference in mass.
Mass of three alpha - Mass of Carbon nucleus
12.0078u - 12u = 0.0078u
Since 1u = 1.66 x 10⁻²⁷ kg
Therefore, 0.0078u = 1.2948 x 10⁻²⁷
Now that we know Mass(m) = 1.2948 x 10⁻²⁷ and Speed (c) 3 x 10⁸ m²s⁻²
Formular for Energy ==> E₀ = mc²
E = (1.2948 x 10⁻²⁷) (3 x 10⁸ m²s⁻²)²
E = (1.2948 x 10⁻²⁷) (9 x 10¹⁶) J
E = 11.6532 x 10⁻¹¹ J
Or, if you need your energy in MeV
1 MeV = 1.60x10⁻¹³ J
Just do the conversion by dividing 11.6532 x 10⁻¹¹ J by 1.60x10⁻¹³ J
It will give you 7.3 MeV
You can use this response or change the words around if you’d like to :)
answer: people can achieve an environmentally sustainable society by recycling, saving water, reducing the amount of household energy use and lastly reselling and donating items!
hope this helps! :)
Answer:
Breh seriously. Ugh fine.
1.B
2.D
3.C
4.C
5.D,A and B
6.A,C and D
Answer:
The component of block weight parallel to the plane, Wₓ = W cosθ
Explanation:
Let the weight of the block due to gravitation is W
The direction of the weight is vertically down
Let θ be the angle formed with the vertical weight of the block and the incline.
Taking two components of weight one along the vertical weight and another component perpendicular to it.
Then the component `of weight long the parallel of the plane is
Wₓ = W cosθ
