<span>You plug this into the ideal gas law, Pv=nrt, (pressure*volume=moles*gas constant*Temperature) because every thing except volume and pressure remain the same, 2.4*14.1=84.6*V. solve for v, and you get .4 L.</span>
Answer:
The temperature at which the vapor pressure of a liquid is just equal to the external ... The conversion of a liquid to a gas below the boiling point is called ... equilibrium temperature of the mixture was 36.0 °C. What is the specific heat (J/ g°C) of the metal
Explanation:
One valence electron is lost by Lithium
<h3>What is Electron ?</h3>
Unattached or attached to an atom, an electron is a negatively charged subatomic particle. One of the three main types of particles within an atom is an electron that is bound to it. The other two are protons and neutrons.
- Due to the fact that full valence shells are more stable states and that all noble gases have them, lithium wants to lose electrons in order to become like helium. Consequently, alkali metals lose one electron to achieve the closest noble gas configuration.
- Each lithium atom loses an electron to become a Li+ cation when it forms chemical compounds with other elements. The anions in ionic compounds that are negatively charged are therefore attracted to these. There are many applications for lithium compounds.
- Since full valence shells are more stable states, and all noble gases have them, lithium wants to lose electrons to become like helium. In order to obtain the nearest noble gas configuration, alkali metals must lose one electron.
Learn more about Electron here:
brainly.com/question/860094
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Answer:
We are given:
V(i) = 0.3 L V(f) = 0.36 L
P(i) = x pa P(f) = 400 pa
T(i) = T(f) = 293 k
Using the gas formula:
PV = nRT
Since n , R and T are constant,
PV = k (where k is a constant)
Hence we can say that:
P(i) * V(i) = P(f) * V(f)
x * 0.3 = 0.36 * 400
x = 14.4/0.3
x = 480 pascals
Hence the initial pressure is 480 pascals
Converting to Kpa, we have to divide by 1000
Initial pressure (Kpa) = 0.48