Consecutive integers are integers that appear one after the other. so let's call them x, x+1, and x+2.
the smallest (which is x) is 15 less than twice the larger. "the larger" is a bit unclear, but i'm assuming it is referring to the x+1 integer, because it doesn't say the "largest". so x = 2(x+1) - 15. let's try to solve for x.
x = 2(x+1) - 15
x = 2x + 2 - 15
x = 2x - 13
subtract 2x from both sides.
-x = -13
x = 13
x+1 = 14
x+2 = 15
your integers are 13, 14, and 15.
Answer:
x = 3
y = 0
Step-by-step explanation:
x + 2y = 3 ---------eqn 1
x - y = 3 --------eqn 2
Using eqn 2 to find the value of y
x - y = 3
Making y the subject of the formula
x - 3 = y
y = x - 3
Substitute the value of y into eqn 1
x + 2y = 3
x + 2(x - 3) = 3
Open the bracket
x + 2x - 6 = 3
3x - 6 = 3
3x = 3 +6
3x = 9
Divide both sides by 3, to get value of x
3x/3 = 9/3
x = 3
To get the value of y, use eqn 2
x - y = 3
3 - y = 3
3 - 3 = y
y = 0
Hint, to know maybe the values are correct, insert the values into the equation
Let's use eqn 2
x - y = 3
x = 3
y = 0
Insert into the equation
x - y = 3
3 - 0 = 3
Our values are correct
Answer:yes
Step-by-step explanation:
Answer: 0.1 I might be wrong tho
Step-by-step explanation:
