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Ivanshal [37]
3 years ago
7

A tree DOUBLES in height each year until it reached its maximum height over the course of 10 years. How many years did it take f

or the tree to reach HALF its maximum height?
Mathematics
1 answer:
RideAnS [48]3 years ago
8 0

Answer:

9 years

the tree doubles in height

we can make a model

1 x 2 = 2

2 x 2 = 4

4 x 2 = 8

8 x 2 = 16

16 x 2 = 32

32 x 2 = 64

64 x 2 = 128

128 x 2 = 256

256 x 2 = 512

512 x 2 = 1024

Let's say 1024 is the maximum height

half the maximum height is 1024 x 0.5 = 512 so it will take 9 years because it reached 512 on the 9th year

Step-by-step explanation:

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13f + 6 -f = -3 <br><br> help?
malfutka [58]

Answer:

f = -3/4

Step-by-step explanation:

13f + 6 -f = -3

Combine like terms

12f +6 = -3

Subtract 6 from each side

12f+6-6 = -3-6

12f = -9

Divide each side by 12

12f/12 = -9/12

f = -3/4

7 0
3 years ago
Read 2 more answers
Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)
viktelen [127]
\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}

The first line segment can be parameterized by \mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle with 0\le t\le1. Denote this first segment by C_1. Then

\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt
=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt
=108

The second line segment (C_2) can be described by \mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle, again with 0\le t\le1. Then

\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt
=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt
=-\dfrac{229}3

Finally,

\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3
5 0
3 years ago
In the isosceles triangle, find a and b if you knew the perimeter was 20x+35
Zanzabum

Answer:

a=8

b=17

Step-by-step explanation:

Isoceles means we will have 2 congruent sides in this triangle.

So it appears we are to assume it is sitting on its base which means that other side has measurement ax+9 as well

So we have the sum of the 3 sides is the perimeter.

That means we have the equation:

(ax+9)+(ax+9)+(4x+b)=20x+35

Combine like terms:

(a+a+4)x+(9+9+b)=20x+35

(2a+4)x+(18+b)=20x+35

This implies 2a+4=20 and 18+b=35.

2a+4=20

Subtract 4 on both sides:

2a=16

Divide both sides by 2:

a=8

18+b=35

Subtract 18 on both sides:

b=17

So a=8 and b=17.

3 0
3 years ago
Complex to Trigonometric:<br>Z=√6+√2+2i​
Alekssandra [29.7K]

Answer:

z=6+2i maybe

Step-by-step explanation:

8 0
3 years ago
what is the equation in slope form of the line that is parallel to the given line and passes through the point (-3,1)​
viktelen [127]

Answer:

D

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Calculate the slope of the given line using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 2, - 4) and (x₂, y₂ ) = (2, 2) ← 2 points on the line

m = \frac{2+4}{2+2} = \frac{6}{4} = \frac{3}{2}

Parallel lines have equal slopes and using (a, b) = (- 3, 1), then

y - 1 = \frac{3}{2}(x - (- 3)), that is

y - 1 = \frac{3}{2}(x + 3) ← in point- slope form

6 0
3 years ago
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