Answer:
0.903264
Step-by-step explanation:
Given that a TV set contains five circuit boards of type A, five of type B, and four of type C. The probability of failing in its first 5000 hours of use is 0.03 for a type A circuit board, 0.04 for a type B circuit board, and 0.03 for a type C circuit board.
Let A' = the event that A fails, B' = B fails and C'= C fails.
Probability that no circuit board fails = Prob (A'B'C')
= P(A')P(B')P(C') (since A,B, C are independent, their complements are independent
= (1-0.03)(1-0.04)(1-0.03)
= 0.903264
40. m∠2=148° m∠4=148°
41. ∠2 and ∠5
42. ∠1 and ∠2
43. ∠3 and ∠5
Sorry, I don't know how to do the rest, but I hope this helps!
The nine rounds up so it would be 400,000
The given answer should be "3/2", its because "32" is not possible in anyway..
tan C = sin C / cos C
Where sin C = 3 / 3.61
And
cos C = 2 / 3.61
Now
tan C = (3 / 3.61) / (2 / 3.61) = (3 / 3.61) x (3.61 /
2) = 3 / 2
<span>Thus tan C is the correct choice. </span>
