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3 years ago

Multiple Choice

Physics

1 answer:

Digiron [165]3 years ago

8 0

Answer:

What was not required by the Massachusetts Education law of 1642 is;

Children were to be sent to designated schoolmaster for their learning

Explanation:

The Law of 1642 required that parents and master see to it that their children knew the principles of religion and the capital laws of the commonwealth.

The important aspects of the 1642 Law includes;

1) The responsibility for the basic education and literacy of a child are those of the parents and masters of child apprentices

2) Reading and writing competency of all children and servants are a requirement

3) It is the duty of the government, where a parent or master are unable to meet their tutoring responsibility, to see that a child is placed where the basic educational requirement will be met.

The role of a schoolmaster or the setting of a formal school were yet to be formed as at that time.

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a girl of mass 40 kg wearing high heel of radius 3mm. find the pressure exerted by her on the ground. [answer the question fast]

kakasveta [241]

You should calculate 40 kg and the radius 3mm.

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3 years ago

The nucleus in an iron atom has a radius of about 4.0 10-15 m and contains 26 protons. (a) What is the magnitude of the repulsiv

zhenek [66]

Answer:

The repulsive electrostatic force between two of the protons is 14.4 N.

Explanation:

Given;

distance between the two protons, r = 4 x 10⁻¹⁵ m

charge of a proton, q = + 1.6 x 10⁻¹⁹ C

The repulsive electrostatic force between two of the protons is calculated by applying Coulomb's law;

$F = \frac{k q_1 q_2 }{r^2} \\\\where;\\k \ is \ Coulomb's \ constant = 9\times 10^9 \ Nm^2/C^2 \\\\F = \frac{9\times 10^9 \ (1.6\times 10^{-19})^2}{(4 \times 10^{-15})^2} \\\\F = 14.4 \ N$

Therefore, the repulsive electrostatic force between two of the protons is 14.4 N.

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3 years ago

The moon's gravity is one-sixth that of the earth. what is the period of a 2.00m long pendulum on the moon

erik [133]

Answer:

6.96 s

Explanation:

The period of a simple pendulum is given by:

$T=2 \pi \sqrt{\frac{L}{g}}$

where

L is the length of the pendulum and g the acceleration due to gravity.

In this problem, we have a pendulum with length L = 2.00 m, while the acceleration due to gravity is 1/6 that of the earth:

$g' = \frac{g}{6}=\frac{9.8 m/s^2}{6}=1.63 m/s^2$

So, the period of the pendulum on the moon is

$T=2 \pi \sqrt{\frac{2.00 m}{1.63 m/s^2}}=6.96 s$

3 0

3 years ago

You have a light spring which obeys Hooke's law. This spring stretches 2.92 cm vertically when a 2.70 kg object is suspended fro

ehidna [41]

(a) 907.5 N/m

The force applied to the spring is equal to the weight of the object suspended on it, so:

$F=mg=(2.70 kg)(9.8 m/s^2)=26.5 N$

The spring obeys Hook's law:

$F=k\Delta x$

where k is the spring constant and $\Delta x$ is the stretching of the spring. Since we know $\Delta x=2.92 cm=0.0292 m$ , we can re-arrange the equation to find the spring constant:

$k=\frac{F}{\Delta x}=\frac{26.5 N}{0.0292 m}=907.5 N/m$

(b) 1.45 cm

In this second case, the force applied to the spring will be different, since the weight of the new object is different:

$F=mg=(1.35 kg)(9.8 m/s^2)=13.2 N$

So, by applying Hook's law again, we can find the new stretching of the spring (using the value of the spring constant that we found in the previous part):

$\Delta x=\frac{F}{k}=\frac{13.2 N}{907.5 N/m}=0.0145 m=1.45 cm$

(c) 3.5 J

The amount of work that must be done to stretch the string by a distance $\Delta x$ is equal to the elastic potential energy stored by the spring, given by:

$W=U=\frac{1}{2}k\Delta x^2$

Substituting k=907.5 N/m and $\Delta x=8.80 cm=0.088 m$ , we find the amount of work that must be done:

$W=\frac{1}{2}(907.5 N/m)(0.088 m)^2=3.5 J$

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3 years ago

How are wavelength and frequency of a wave related?

Nesterboy [21]

Wavelength is the length from one peak of a wave to the next, while frequency is the amount of waves present in a unit of time. The greater the wavelength the smaller the frequency. The smaller the wavelength, the bigger the frequency.

8 0

3 years ago

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