All categories

3 years ago

How much heat is needed to raise the temperature of 6g of water by 19oC?

1 answer:

5 0

First we have to convert 6 grams to kg (0.006 kg) and then using the thermal physics formula which is Q=m*c*change in temperature, we get 478,8 joule
(Btw c is the specific heat capacity of water which is 4200 j/kg °C

You might be interested in

Explain what is happening when roller coaster is at each point. **The roller coaster has started at A and goes to D.

yaroslaw [1]

Answer:

At point A, the cart has high potential energy. At point b, the cart is pulled down by gravity. At point c, the cart gains its highest kinetic energy. At point d, the cart returns back to the same state but with lower potential energy.

3 0

2 years ago

Describe the Pascal's principles

boyakko [2]

Explanation:

Pascal's principle, also called Pascal's law, in fluid (gas or liquid) mechanics, statement that, in a fluid at rest in a closed container, a pressure change in one part is transmitted without loss to every portion of the fluid and to the walls of the container.

3 0

3 years ago

A teapot with a surface area of 700 cm2 is to be plated with silver. It is attached to the negative electrode of an electrolytic

Brums [2.3K]

Jjanaajjjajajjaajjajaja

5 0

3 years ago

With a thunderstorm brewing, an electric field of magnitude 2.0 × 102 newtons/coulomb exists at a certain point in the earth’s a

hichkok12 [17]

(2.0 x 10² N/Coul) x (-1.6 x 10⁻¹⁹ Coul) = -3.2 x 10⁻¹⁷ N

The magnitude is 3.2 x 10⁻¹⁷ Newton.

3 0

3 years ago

an object is acted on by a drag force with a magnitude that is proportional to the speed. the object accelerates downward at 3.0

Nutka1998 [239]

The terminal speed of the object falling down is 66.67 m/s.

The terminal speed acquired by the body when,

Weight of the body = Drag force of the body

It is given,

Drag force is directly proportional to the speed,

So,

F = CV

Where F is drag force,

V is the speed,

C is the constant,

So, it can be written as C = F/V.

The weight of the body = mg

The weight of the body = 10m

M is the mass and g is the acceleration due to gravity,

The drag force when the speed is 20m/s.

Drag force = ma

a is the acceleration during the drag force which is given to be 3m/s²,

Drag force = 3m

Now we can write,

F₁/V₁ = F₂/V₂

F₁ is the drag force at 20m/s speed.

F₂ is the weight of the body and V₂ is the terminal speed,

Now, it can be written,

3m/20 = 10m/V₂

V₂ = 66.67 m/s.

So, the terminal speed is 66.67m/s.

To know more about terminal speed, visit,

brainly.com/question/14605362

#SPJ4

7 0

1 year ago