Answer:
9.21954 m/s
54 m/s²
Angle is zero
Explanation:
r = Radius of arm = 1.5 m
= Angular velocity = 6 rad/s
The horizontal component of speed is given by

The vertical component of speed is given by

The resultant of the two components will give us the velocity of hammer with respect to the ground

The velocity of hammer relative to the ground is 9.21954 m/s
Acceleration in the vertical component is zero
Net acceleration is given by

Net acceleration is 54 m/s²
As the acceleration is towards the center the angle is zero.
Hello!
For the explanation of this energy conservation exercise, where we'll use <u>energy conservation law</u>, let's see what this principle proposes.
How you should know, mechanical energy conserves in every point, that is to say mechanical energy is same in A point like B point. (Mechanical energy will be represented by "Me")
Once time we know that, let's take the 220 Joules momentum like A point, and when 55 Joules momentum like B point.
Then, let's use the <u>energy conservation principle:</u>
Me(A) = Me(B)
- We know Mechanical energy in A point, so just lets replace according to our data:
220 J = Me(B)
- In B point, we know kinetic energy, but <u>we dont know gravitational potential energy</u>, so lets descompose Mechanical energy, into kinetic energy and gravitational potential energy:
220 J = Ke + Gpe
- We know kinetic energy value, so lets replace it:
220 J = 55 J + Gpe
- Finally, just clean Gpe and resolve it:
Gpe = 220 J - 55 J = 165 J
Gravitational potential energy is of One hundred sixty five Joules <u>(165 J).</u>
║Sincerely, ChizuruChan║
Answer:
a) please find the attachment
(b) 3.65 m/s^2
c) 2.5 kg
d) 0.617 W
T<weight of the hanging block
Explanation:
a) please find the attachment
(b) Let +x be to the right and +y be upward.
The magnitude of acceleration is the same for the two blocks.
In order to calculate the acceleration for the block that is resting on the horizontal surface, we will use Newton's second law:
∑Fx=ma_x
T=m1a_x
14.7=4.10a_x
a_x= 3.65 m/s^2
c) <em>in order to calculate m we will apply newton second law on the hanging </em>
<em> block</em>
<em> </em>∑F=ma_y
T-W= -ma_y
T-mg= -ma_y
T=mg-ma_y
T=m(g-a_y)
a_x=a_y
14.7=m(9.8-3.65)
m = 2.5 kg
<em>the sign of ay is -ve cause ay is in the -ve y direction and it has the same magnitude of ax</em>
d) calculate the weight of the hanging block :
W=mg
W=2.5*9.8
=25 N
T=14.7/25
=0.617 W
T<weight of the hanging block
Answer:
I would say A
Explanation:
I don't think it's B because depending on where it fell it might not go into motion and your passengers feeling uncomfortable isn't a danger
Answer:
c. equal to 760 mm
Explanation:
We are told that another mercury barometer is used that has a tube of larger diameter. This means a larger area and the weight of the liquid in the tube will have increased since volume = area × height. Also, due to the larger area, the net upward force
on the mercury will have also increased by the
same amount because force = area × pressure. Therefore, as long as the pressure remains the same, the height of
the mercury will also remain the same.
Thus the height of the mercury = 760 mm