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3 years ago

Convert 5.7 miles to km

Physics

2 answers:

SVEN [57.7K]3 years ago

7 0

9.17

i think its the answer i just took the test and got it correct

gayaneshka [121]3 years ago

4 0

5.7 kilometers is equal to 3.5418157957528034 miles

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True or false: Scientific models are always built to scale, and are fully functional representations of the product they are tes

vodka [1.7K]

Answer:

False

Explanation:

Scientific models are not always built to scale and may not be fully accurate

3 0

2 years ago

How long will it take for a spacecraft traveling at

zzz [600]

Answer:

16 2/3 hr

Explanation:

250 000 km / 15 000 km/hr = 16 2/3 hours

5 0

2 years ago

The distribution of total body protein in healthy adult men is approximately Normal, with mean 12.3 kg and standard deviation 0.

Sophie [7]

Answer:

$P(12.25\leq x \leq 12.35 ) = 0.9876$

Explanation:

given,

mean (μ) = 12.3 Kg

standard deviation (σ ) = 0.1

random sample = 25

probability between 12.25 and 12.35 kg

$P(12.25\leq x \leq 12.35 ) = P(\dfrac{12.35-12.3}{\dfrac{0.1}{\sqrt{n}}}\leq z)- P(\dfrac{12.25-12.3}{\dfrac{0.1}{\sqrt{n}}}\leq z)$

$P(12.25\leq x \leq 12.35 ) = P(\dfrac{12.35-12.3}{\dfrac{0.1}{\sqrt{25}}}\leq z)- P(\dfrac{12.25-12.3}{\dfrac{0.1}{\sqrt{25}}}\leq z)$

$P(12.25\leq x \leq 12.35 ) = P(\dfrac{12.35-12.3}{\dfrac{0.1}{5}}\leq z)- P(\dfrac{12.25-12.3}{\dfrac{0.1}{5}}\leq z)$

$P(12.25\leq x \leq 12.35 ) = P(\dfrac{5 (12.35-12.3)}{0.1}\leq z)- P(\dfrac{5(12.25-12.3)}{0.1}\leq z)$

$P(12.25\leq x \leq 12.35 ) = P(\dfrac{2.5\leq z)- P(-2.5\leq z)$

using z-table

$P(12.25\leq x \leq 12.35 ) = 0.9938 - 0.0062$

$P(12.25\leq x \leq 12.35 ) = 0.9876$

4 0

3 years ago

If a car is traveling at 35 mph how far will the car travel in 2.5 hours

Vanyuwa [196]

Answer:

87.5 miles

Explanation:

d = s * t

d = 35 * 2.5

d =87.5

4 0

3 years ago

A toy rocket is launched straight up by using a spring. The rocket is initially pressed down on the spring so that the spring is

tigry1 [53]

Answer:

6.86 meters

Explanation:

Let the compression of the string be represented by x, and the height of projection of the toy rocket be represented by h.

So that;

x = 9 cm = 0.09 m

In its rest position (i.e before the launch), the spring has a stored potential energy which is given as;

PE = $\frac{1}{2}$ K $x^{2}$

= $\frac{1}{2}$ x 830 x $(0.09)^{2}$

= 415 x 0.0081

= 3.3615

The potential energy in the string = 3.36 Joules

Also,

PE = mgh

where: m is the mass, g is the gravitational force and h the height.

m = 50 g = 0.05 kg, g = 9.8 m $s^{-2}$

Thus,

PE = 0.05 x 9.8 x h

3.3615 = 0.05 x 9.8 x h

3.3615 = 0.49h

⇒ h = $\frac{3.3615}{0.49}$

= 6.8602

The height of the toy rocket would be 6.86 meters.

4 0

2 years ago