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Rudik [331]
2 years ago
13

If 2 ma of current flow in your mp3 player, how long will it take for 1 c of charge to flow?

Physics
1 answer:
Mrrafil [7]2 years ago
7 0

If 2 ma of current flow in your mp3 player, 8.3 mins or 500 sec will take for 1 c of charge to flow.

Electric Charge

Charged material experiences a force when it is exposed to an electromagnetic field due to the physical property of electric charge. You can have a positive or negative electric charge (commonly carried by protons and electrons respectively). Unlike charges attract one another while like charges repel one another. Neutral refers to an object that carries no net charge. Classical electrodynamics, the name given to an early understanding of how charged particles interact, is still accurate for issues that do not call for taking into account quantum phenomena.

The coulomb (C), which bears the name of French physicist Charles-Augustin de Coulomb, is the SI-derived unit of electric charge. The charge symbol, lowercase q, is frequently used.

To learn more about the electric charge refer here:

brainly.com/question/9194793

#SPJ4

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The answer is A.68 degrees

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Suppose your surface body temperature averaged 90 degrees F. How much radiant energy in W/m^2 would be emitted from your body?
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493 \; \text{W}\cdot \text{m}^{-2}.

<h3>Explanation</h3>

The Stefan-Boltzmann Law gives the energy radiation <em>per unit area</em> of a black body:

\dfrac{P}{A} = \sigma \cdot T^{4}

where,

  • P the total power emitted,
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\sigma = 5.67 \times 10^{-8} \;\text{W}\cdot \text{m}^{-2} \cdot \text{K}^{-4}.

T = 90 \; \textdegree{}\text{F} = (\dfrac{5}{9} \cdot (90-32) + 273.15) \; \text{K} = 305.372 \; \text{K}.

\dfrac{P}{A} = \sigma \cdot T^{4} = 5.67 \times 10^{-8} \times 305.372^{4} = 493\; \text{W}\cdot \text{m}^{-2}.

Keep as many significant figures in T as possible. The error will be large when T is raised to the power of four. Also, the real value will be much smaller than 493\; \text{W}\cdot \text{m}^{-2} since the emittance of a human body is much smaller than assumed.

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Find the center of the galaxy with Shapley method
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since the object is moving at an escape velocity which is 11.2m/s the object will be assumed to be weightless

Etotal = kinetic energy + potential energy

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Etotal=0+0

Etotal=0.

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