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alina1380 [7]
3 years ago
14

PLEASE HELP! FOR BRAINLIEST!!!

Physics
2 answers:
Stells [14]3 years ago
7 0

Answer:

I think it's C I'm so sorry if I'm wrong.

Explanation:

SVETLANKA909090 [29]3 years ago
7 0

Answer:

<h2><em>A or</em> <em>Alex > Chai > Jimmy > Sanni</em></h2>

Explanation:

__________________________________________________________

<em>Here's why this is the answer,</em>

<em>__________________________________________________________</em>

<em>Alex's Range = 3.20 - 0.90 = 2.30</em>

<em>Sanni's Range = 1.35 - 1.30 = 0.05</em>

<em>Chai's Range = 2.10 - 1.05 = 1.05</em>

<em>Jimmy's Range = 2.20 - 1.55 = 0.65</em>

__________________________________________________________

<u>Greatest to Least</u>

<em>Alex > Chai > Jimmy > Sanni</em>

<em>Here's why this is correct.</em>

<em>Alex = 2.30</em>

<em>Chai = 1.05</em>

<em>Jimmy = 0.65</em>

<em>Sanni = 0.05</em>

<em>I do not see the answer I have on this question so I think it is A.</em>

<em>__________________________________________________________</em>

<em>Hope this helps! <3</em>

<em>__________________________________________________________</em>

<em></em>

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3.Cuanto Calor pierden 514 ml de agua si su temperatura desciende de 12°C a 11°C. Expresa el resultado en calorias.
Scrat [10]

Answer:

514 cal

Explanation:

In order to calculate the lost heat by the amount of water you first take into account the following formula:

Q=mc(T_2-T_1)         (1)

Q: heat lost by the amount of water = ?

m: mass of the water

c: specific heat of water = 1cal/g°C

T2: final temperature of water = 11°C

T1: initial temperature = 12°C

The amount of water is calculated by using the information about the density of water (1g/ml):

m=\rho V=(1g/ml)(514ml)=514g

Then, you replace the values of all parameters in the equation (1):

Q=(514g)(1cal/g\°C)(11\°C-12\°C)=-514cal

The amount of water losses a heat of 514 cal

3 0
4 years ago
Both matter waves and electromagnetic waves transfer energy.<br> -True<br> -False
const2013 [10]

Answer:

-T

Explanation:

Hope it helps!

4 0
3 years ago
Coherent light that contains two wavelengths, 660 nm (red) and 470 nm (blue), passes through two narrow slits that are separated
WITCHER [35]

Answer:

0.002699 m or 2.699 mm

Explanation:

y = Fringe distance

d= Distance between slits = 0.310mm

L = Screen distance = 4.40m

λ= Wavelength

Given from question

λ₁= 660 nm = 6.6 x 10^-9 m

λ₂= 470 nm = 4.7 x 10^-9 m

d = 0.340 mm = 3.4 x 10^-3 m

L = 4.40 m

In the case of constructive interference, we use below formula

y/L = mλ/d

For first order wavelength

(y₁/4.40) =(1×660x10⁻⁹)/(0.310*10⁻³)

y₁= (0.310*10⁻³)×(4.40)/(0.310*10⁻³)

y₁=0.00937m

(y2/4.40) =(1×470x10⁻⁹)/(0.310*10⁻³)

y2= =(1×470x10⁻⁹)×(4.40)/(0.310*10⁻³)

y2=0.00667m

distance between the fringes is given by (y₁ -y2)

=0.00937-0.00667=0.002699m

Therefore, distance on the screen between the first-order bright fringes for the two wavelengths is 0.002699 m or 2.699 mm

8 0
3 years ago
The drawing shows a hydraulic chamber with a spring (spring constant = 1600 N/m) attached to the input piston and a rock of mass
Triss [41]

Answer:

\Delta x=245\ mm

Explanation:

Given:

  • spring constant of the spring attached to the input piston, k=1600\ N.m^{-1}
  • mass subjected to the output plunger, m=40\ kg

<u>Now, the force due to the mass:</u>

F=m.g

F=40\times 9.8

F=392\ N

<u>Compression in Spring:</u>

\Delta x=\frac{F}{k}

\Delta x=\frac{392}{1600}

\Delta x=0.245\ m

or

\Delta x=245\ mm

8 0
4 years ago
An inductor is connected to an AC generator. As the generator's frequency is increased, the current in the inductor A. Increases
Luda [366]

Answer:

B) Decrease

Explanation:

Resistance offered due to inductor in any AC circuit is given as

X_L = \omega L

here we know that

\omega = angular frequency

\omega = 2\pi f

now by ohm's law we know that

i = \frac{V}{X}

here we have

i = \frac{V}{\omega L}

so current is inversely depends on the frequency of AC

so if frequency is increased then the current will decrease

6 0
3 years ago
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