Yes if we use the resource up before it can renew itself then it could be used up and be depleted or near depletion. The resource has to have time to come back and if we use it up to fast then the resource can not take the time it needs to come back.
Answer:
I would expect to extract the acetic acid.
Explanation:
In the first step, since we are adding a concentrated acid,<u> it will react with the bases present in the mixture (diethylamine and ammonia) </u><u>forming salts</u><u>, </u><u>which are soluble in water</u>. Therefore, after draining the aqueous layer, we will have phenol and acetic acid left in the organic layer.
In the second step, we are adding a diluted base, so it will react with a strong acid. This compound is acetic acid, and its salt will be present in the aqueous layer. Phenol will be left on the organic layer.
Answer:
The answer is 916.67 g
Explanation:
48.0 wt% NaOH means that there are 48 g of NaOH in 100 g of solution. With this information and the molecular weight of NaOH (40 g/mol), we can calculate the number of mol there are in 100 g of this solution:
x 
= 0.012 mol NaOH/100 g solution
Finally, we need 0.11 mol in 1 liter of solution to obtain a 0.11 M NaOH solution.
0.012 mol NaOH ------------ 100 g solution
0.11 mol NaOH------------------------- X
X= 0.11 mol NaOH x 100 g/ 0.012 mol NaOH= 916.67 g
We have to weigh 916.67 g of 48.0%wt NaOH and dilute it in a final volume of 1 L of water to obtain a 0.11 M NaOH solution.
I believe it is happening more towards the middle states of the US...
Answer:
the coefficient of y is -7
