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Vladimir79 [104]
3 years ago
8

Which pair of elements can form ionic bonds?

Chemistry
2 answers:
Oxana [17]3 years ago
7 0

Answer:

Correct answer: E.  potassium (K) and bromine (Br)

Explanation:

(Correct answer for (portal and Edmentum users too)

Hope I was helpful :) good luck on your school work and have a great day

Sindrei [870]3 years ago
3 0

Answer:

E.  potassium (K) and bromine (Br)

Explanation:

An ionic bond is formed between compounds with a large electronegativity difference between them. It is usually between a metal and non-metal.

  • Potassium is a true metal found in group 1 on the periodic table.
  • Bromine is a highly electronegative non-metal which is a halogen.
  • Potassium will lose one of its electrons which will be gained by the Bromine.
  • The electrostatic attraction between the two species will cause the ionic bond to form.
  • The ability of one specie willing to lose electron and the other gaining, is the main bed rock of ionic bonding.
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Water/H20 is a compound made of hydrogen and oxygen. Although water is the most abundant substance on earth, it is rarely found naturally in its pure form. Most of the time, pure water has to be created. Pure water is called distilled water or deionized water.

Explanation:

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As the temperature of a liquid increases, its viscosity _____. increases stays the same decreases
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As the temperature of a liquid increases, its viscosity decreases.
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What parts do all cells have?
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All cells have these four parts in common: a plasma membrane, cytoplasm, ribosomes, and DNA

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Prandtl number in heat transfer analogues to which dimension less number in mass transfer. a) Schmidt number b) Sherwood number
Cloud [144]

Answer:

a) Schmidt number

Explanation:

Prandtl number in heat transfer is analogues to Schmidt number in mass transfer.

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5 0
3 years ago
What’s the answer ?
Romashka-Z-Leto [24]

Answer:

45.3°C

Explanation:

Step 1:

Data obtained from the question.

Initial pressure (P1) = 82KPa

Initial temperature (T1) = 26°C

Final pressure (P2) = 87.3KPa.

Final temperature (T2) =.?

Step 2:

Conversion of celsius temperature to Kelvin temperature.

This is illustrated below:

T(K) = T(°C) + 273

Initial temperature (T1) = 26°C

Initial temperature (T1) = 26°C + 273 = 299K.

Step 3:

Determination of the new temperature of the gas. This can be obtained as follow:

P1/T1 = P2/T2

82/299 = 87.3/T2

Cross multiply to express in linear form

82 x T2 = 299 x 87.3

Divide both side by 82

T2 = (299 x 87.3) /82

T2 = 318.3K

Step 4:

Conversion of 318.3K to celsius temperature. This is illustrated below:

T(°C) = T(K) – 273

T(K) = 318.3K

T(°C) = 318.3 – 273

T(°C) = 45.3°C.

Therefore, the new temperature of the gas in th tire is 45.3°C

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3 years ago
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