Actually since Bromine is located at the 1 Carbon, so we
can say that this is a primary alkyl halide and which undergoes SN2 or E2
reactions. This reaction is a bimolecular, single step process because it is a
primary.
<span>The substitution product formed will be 1-ethoxybutane
(main product) and sodium bromide (side product).</span>
Answer:
The temperature of the system once the equilibrium has been reached = 372.55K
Explanation:
Heat capacity of gold = 129 J/Kg*c.
Heat capacity of water
4,184 J/Kg*c.
Mass of gold = 75g = 0.075Kg
Mass of water = 200g = 0.2Kg
From conservation of energy
m1×C1×(t11 - t2) = m2×C2×(t2- t21)
Substituting we have
0.075 × 129×(1000-t2) = 0.2× 4184×( t2 -300) =solving for t2, we have
933.55×t2 = 347790
or t2 = 372.55K
The temperature of the system once the equilibrium has been reached = 372.55K
Can u send me the link ? Sorry tho but I don’t know how to go to ur questions :(
The volume of 15.7 M H2SO4 is required to prepare 12.0 L of 0.156 M sulfuric acid is 0.12 L
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Molarity of stock solution (M₁) = 15.7 M
- Volume of diluted solution (V₂) = 12 L
- Molarity of diluted solution (M₂) = 0.156 M
- Volume of stock solution needed (V₁) = ?
<h3>How to determine the volume of the stock solution needed</h3>
The volume of the stock solution needed can be obtained by using the dilution formula as shown below:
M₁V₁ = M₂V₂
15.7 × V₁ = 0.156 × 12
15.7 × V₁ = 1.872
Divide both side by 15.7
V₁ = 1.872 / 15.7
V₁ = 0.12 L
Thus, the volume of the stock solution needed to prepare the solution is 0.12 L
Learn more about dilution:
brainly.com/question/15022582
#SPJ1
Answer:
Elliptical galaxies are one of the three types of galaxies. They have a rounded shape of an ellipse, like a stretched-out circle. They lack the swirling arms that are a main feature of spiral galaxies.
