How can you use qualitative properties to identify a gas sample?

Calculate the number of moles of O2 produced using the ideal gas law. Then, use this value to calculate the number of moles of h

aev [14]

Answer:Given data from the lab collated as 291.15k for Temperature, 0.061L for volume and 1atm pressure.

Initial hydrogen peroxide solution is 5ml with a weigh % concentration 6.6%

n=0.0025moles of oxygen AND 0.0097moles of H2O2 were present

Explanation:

2H2O2(aq)-----2H2O(I)+2O2(g)

Recall the idea gas equation

PV=nRT

n=PV/RT---(1) solving equation (1) using the data in the answer section above.

n=0.0025moles of oxygen is produced.

Recall that for every 100ml of solution you get 6.6g of hydrogen peroxide.

Your 5ml will thus contain

5ml*6.6g H2O2/100ml=0.33g

no of moles if H2O2=0.33/34.015=0.0097moles

6 0

3 years ago

(50 POINTS) HELPPP

Debora [2.8K]

The answer is D, Magnesium.

For an anion or cation(negatively or positively charged ion) to replace a similarly-charged ion, it needs to be more active. This means that only a cation that is above Zinc on the reactivity scale can replace Zinc.

Since Aluminum was displaced in the reaction, that means the unknown metal is more reactive.
This means that our options are:
Lithium, Potassium, Calcium, Sodium, and Magnesium.

But because the metal did not displace the Sodium, it must be less reactive than it.
This gives us a new list of metals that are less-reactive than Sodium:
Magnesium, Aluminum, Zinc, Iron, Nickel, etc.

The only metal on both lists is Magnesium, and that means that your answer is D, Magnesium.

8 0

3 years ago

50 grams of acetic acid C2H4O2 are dissolved in 200 g of water. Calculate the weight % and mole fraction of the acetic acid in t

Len [333]

$50g$ $of$ $C_2H_4O_2$ $in$ $200g$ $H_2O$

so:

$\frac{50}{200+50}+100\%= \frac{50*100}{250}\%=20\%$

$MW of acid = 2*C+4*H+2*O = 2*12+4*1+2*16=$

$=24+4+32=60g/mol$

so:

$\frac{50g}{60g/mol}\approx0.83moles$

it means that

in $50g$ of acid there is $\approx0.83$ moles of acid

$MW of H_2O = 2*H+O=2*1+16=2+16=18g/mol$

so:

$\frac{200g}{18g/mol}\approx11.11moles$

it means that:

in $200g$ of water there is $\approx11.11$ moles of water

therefore:

$\frac{0.83mol}{11.11mol+0.83mol}= \frac{0.83mol}{11.94mol}=0.069$

So your answers are:

$20\%$

and the mole fraction is:

$0.069$

6 0

4 years ago

Sydney was organizing a box of resistors by resistance range. She knows that there are several factors that go into determining

kati45 [8]

The resistance of the wire is dependent on temperature, diameter and nature of the material.

<h3>What is resistance?</h3>

The term resistance refers to the opposition offered to the flow of current in a circuit. The resistance is obtained form Ohm's law which states that;

V = IR

Where;

V = voltage

I = current

R = resistance

Hence, the resistance is dependent on;

temperature
diameter
material

Learn more about resistance: brainly.com/question/15067823

7 0

2 years ago

*

Temka [501]

Salt dissolving in water is usually considered to be a physical change so I’m pretty sure it’s that sorry if I’m wrong

6 0

3 years ago