Ask question

Ask question

All categories

3 years ago

8

How can you use qualitative properties to identify a gas sample?

1 answer:

laila [671]3 years ago

3 0

The answer is b flame test

You might be interested in

Is a cube of salt being crushed before being stirred into water a physical or chemical change

Olin [163]

By crushing the salt, you are performing a physical change because you aren't altering the chemical makeup of the salt, just the physical form. Hope this helps! :)

6 0

2 years ago

Read 2 more answers

Which total mass is the smallest?

andreev551 [17]

The mass of electrons, protons, and neutrons:
electrons 9.10938291*10^-31 kg
protons 1.67262178*10^-27 kg
neutrons 1.6749*10^-27 kg
the mass of electrons is way smaller than both, the mass of protons and neutrons
therefore, 1) the mass of 2 electrons is the smallest

8 0

3 years ago

What host is used to make the flu vaccine and why can this host be a problem for some people?

valentinak56 [21]

Chicken eggs are used as host and this can be a problem for people with egg allergies!!

6 0

3 years ago

What is the equation for density?<br> O D= m<br> V<br> OD=V<br> m<br> OD=m<br> OD=mv²

frosja888 [35]

Answer:

D = m/V

Explanation:

Density represents the following ratio:

Density (D) = mass (m) / volume (V)

In this formula, the volume is being divided from the mass. The typical units for mass is grams and the unit for volume is milliliters.

4 0

2 years ago

A water treatment plant receives the source water with an average Ca2+ concentration of 46.9 mg/L and Mg2+ concentration of 14.8

Veronika [31]

Answer:

42,650 kg of calcium carbonate will be produced everyday.

13,600.5 kg of magnesium hydroxide will be produced everyday.

Explanation:

Concentration of calcium ions = 46.9 mg/L

Concentration of magnesium ions = 14.8 mg/L

Volume of solution treated everyday , V= 80 million gal

= $80\times 10^6 gal=4.546\times 80\time 10^6 L=3.637\times 10^8 L$

1 gallon = 4.546 Liter

Mass of calcium ion in V = $46.9 mg/L\times 3.637\times 10^8 L$

= $1.706\times 10^{10} mg$

1 mg = 0.001 g

$1.706\times 10^{7} g$

Moles of calcium ions = $\frac{1.706\times 10^{7} g}{40 g/mol}=426,500 mol$

From 1 mole of calcium ion 1mol of carbonate is formed . then from 426,500 moles of calcium ion will form :

$\frac{1}{1}\times 426,500 mol=426,500 mol$ of calcium carbonate

Mass of 426,500 moles of calcium carbonate:

426,500 mol × 100 g/mol = 42,650,000 g = 42,650 kg

Mass of magnesium ion in V = $14.8 mg/L\times 3.637\times 10^8 L$

= $5.382\times 10^{9} mg$

= $5.382\times 10^{6} g$

Moles of magnesium ions = $\frac{5.382\times 10^{6} g}{24 g/mol}=224,250 mol$

From 1 mole of magnesium ion 1 mol of magnesium hydroxide is formed . then from 224,250 moles of magnesium ion will form :

$\frac{1}{1}\times 224,250 mol=224,250 mol$ of magnesium hydroxide

Mass of 224,250 moles of magnesium hydroxide:

224,250 mol × 58 g/mol = 13,006,500 g = 13,006.5 kg

42,650 kg of calcium carbonate will be produced everyday.

13,600.5 kg of magnesium hydroxide will be produced everyday.

3 0

3 years ago