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A. Calculate the diffraction limit of the human eye, assuming a wide-open pupil so that your eye acts like a lens with diameter

myrzilka [38]

A. The Dawes limit tells us that the resolving power is equal to 11.6 / d, where d is the diameter of the eye’s pupil in units of centimeters. The eye's pupil can dialate to approximately 7 mm, or 0.7 cm. So 11.6 / .7 = 16.5 arc seconds, or about a quarter arc minute ~ 17 arc seconds

Although, the standard answer for what people can really see is about 1 arc minute.

B. It is considered as linear, so given a 10 meter telescope (10,000 mm):

10000 / 7 = 1428 times better for the 10 meter scope ~ 1400 times better (in 2 significant figures)

C. For a 7 cm interferometer, that is just similar to a 7 cm scope. Therefore we would expect

11.6 / 7 = 1.65 arc seconds ~ 1.7 arc seconds

This value is what we typically can get from a 7 cm scope.

6 0

3 years ago

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How does temperature influence the appearance of a star? Give an example in your response.

loris [4]

The cooler the temp of the star the star would appear to glisten a red. if the star is warmer the star would be a light blue or blue. An example would be the tiny red dwarf stars. they only have 7% of the suns heat so they appear red.

5 0

3 years ago

How you can speed up the dissolving process when preparing juice from frozen concentrate

Katyanochek1 [597]

If you stir the juice it increases the surface area.

8 0

3 years ago

Which research method uses questionnaires to collect information about the participants in a study?

musickatia [10]

Survey research method uses questionnaires to collect information about the participants in a study.It is commonly used method of collecting information about a population of interest.

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3 years ago

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1.An elevator is ascending with constant speed of 10 m/s. A boy in the elevator throws a ball upward at 20 m/ a from a height of

laiz [17]

(a) The maximum height reached by the ball from the ground level is 75.87m

(b) The time taken for the ball to return to the elevator floor is 2.21 s

The given parameters include:

constant velocity of the elevator, u₁ = 10 m/s

initial velocity of the ball, u₂ = 20 m/s

height of the boy above the elevator floor, h₁ = 2 m

height of the elevator above the ground, h₂ = 28 m

To calculate:

(a) the maximum height of the projectile

total initial velocity of the projectile = 10 m/s + 20 m/s = 30 m/s (since the elevator is ascending at a constant speed)

at maximum height the final velocity of the projectile (ball), v = 0

Apply the following kinematic equation to determine the maximum height of the projectile.

$v^2 = u^2 + 2(-g)h_3\\\\where;\\\\g \ is \ the \ acceleration \ due \ to\ gravity = 9.81 \ m/s^2\\\\h_3 \ is \ maximum \ height \ reached \ by \ the \ ball \ from \ the \ point \ of \ projection\\\\0 = u^2 -2gh_3\\\\2gh_3 = u^2 \\\\h_3 = \frac{u^2}{2g} \\\\h_3 = \frac{(30)^2}{2\times 9.81} \\\\h_3 = 45.87 \ m$

The maximum height reached by the ball from the ground level (h) = height of the elevator from the ground level + height of he boy above the elevator + maximum height reached by elevator from the point of projection

h = h₁ + h₂ + h₃

h = 28 m + 2 m + 45.87 m

h = 75.87 m

(b) The time taken for the ball to return to the elevator floor

Final height of the ball above the elevator floor = 2 m + 45.87 m = 47.87 m

Apply the following kinematic equation to determine the time to return to the elevator floor.

$h = vt + \frac{1}{2} gt^2\\\\where;\\\\v \ is \ the \ initial \ velocity \ of \ the \ ball \ at \ the \ maximum \ height = 0\\\\h = \frac{1}{2} gt^2\\\\gt^2 = 2h\\\\t^2 = \frac{2h}{g} \\\\t = \sqrt{\frac{2h}{g}} \\\\t = \sqrt{\frac{2\times 47.87}{9.81}} \\\\t = 2.21 \ s$

To learn more about projectile calculations please visit: brainly.com/question/14083704

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3 years ago