When is at the end of the runway the velocity of the plane is given by the equation

where s=1800 m is the runway length. Thus
At half runway the velocity of the plane is

Therefore at midpoint of runway the percentage of takeoff velocity is
‰
We know, s = ut + 1/2gt²
In free-fall, u = 0
so, t = √2s/g
Now, substitute the values,
t = √2*4 / 9.8 [ -ve sign shows opposite direction only ]
t = √8/ 9.8
t = 0.90 sec
In short, Your Answer would be 0.90 sec
Hope this helps!
The correct answer would be 1.375 < t < 3 i hope this helps anyone
Magnitude of displacement means the total displacement. Basically taking your final distance and subtracting it from your initial distance so it would be 14m