Answer:
a) 0.658 seconds
b) 0.96 inches
Explanation:

Time taken by the ball to reach the highest point is 0.14 seconds

The highest point reached by the snowball above its release point is 0.315 ft
Total height the snowball will fall is 4+0.315 = 4.315 ft

The snowball will reach the bank at 0.14+0.518 = 0.658 seconds after it has been thrown


The snowball goes 0.5-0.42 = 0.08 ft = 0.96 inches
Answer:
force-strength,power or energy as an attribute of motion, movement or action. Example: Frictional force.
Hahahahha ok it’s B or C or it B
Answer:
(a) 42 N
(b)36.7 N
Explanation:
Nomenclature
F= force test line (N)
W : fish weight (N)
Problem development
(a) Calculating of weight of the heaviest fish that can be pulled up vertically, when the line is reeled in at constant speed
We apply Newton's first law of equlibrio because the system moves at constant speed:
∑Fy =0
F-W= 0
42N -W =0
W = 42N
(b) Calculating of weight of the heaviest fish that can be pulled up vertically, when the line is reeled with an acceleration whose magnitude is 1.41 m/s²
We apply Newton's second law because the system moves at constant acceleration:
m= W/g , m= W/9.8 , m:fish mass , W: fish weight g:acceleration due to gravity
∑Fy =m*a
m= W/g , m= W/9.8 , m:fish mass , W: fish weight g:acceleration due to gravity
F-W= ( W/9.8 )*a
42-W= ( W/9.8 )*1.41
42= W+0.1439W
42=1.1439W
W= 42/1.1439
W= 36.7 N
Answer:
The pendulum frequency is (c) the same, or very close to it
Explanation:
The simple pendulum corresponds to a simple harmonic movement, to reach this approximation in the expression of the force the sine of the angle (θ) approaches an angle value, this is only true for small angles, generally less than 15º
Sine (15th) = 0.2588
The angle in radians is 15º π / 180º = 0.26180.2588 / 0.2618
The difference between these two values is less than 1.2%
for smaller angle the difference is reduced more
Therefore, the period for both the 5º and 10º angles is almost the same