For domain 2x sqrt(2+x)>0
x>0,2+x>0,x>-2 combining
we get x>2
f'(x)=[1/{2x sqrt(2+x)}][{2x/(2 sqrt(2+x))}+2 sqrt(2+x)]
Step-by-step explanation:
where is the question huh ?
Answer: 245y^15
Step-by-step explanation:
Answer:
2.84
Step-by-step explanation:
Recognize that 252 = 7*36
and so:
log base 7 of 252 = log base 7 of 36 + log base 7 of 7, or
log base 7 of 36 + 1
So the most you can simplify log base 7 of 252 is to write 1 + log base 7 of 36.
Or, if you want to use the change of base formula, you could do the following:
log 36
log base 7 of 36 = -------------- = 1.84
log 7
and so log base 7 of 252 would come out to
1 + log base 7 of 36 = 1 + 1.84 = 2.84
Check: does 7^2.84 = 252? YES. So we know that:
1 + log base 7 of 36 = 2.84
Answer:
Tim is a shorter route lara is greater!
Step-by-step explanation: