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Romashka-Z-Leto [24]
3 years ago
13

Which of the following circles have their centers in the third quadrant? Check all that apply.

Mathematics
2 answers:
tester [92]3 years ago
8 0

Answer:

B and D

Step-by-step explanation:

The center of the first one is (-3,6)

The center of the second one is (-9,-12)

The center of the third one is (-14,14)

The center of the fourth one is (-16,-3)

The first one has center in the 2nd

The second one has center in 3rd

The third one has center in the 2nd

The fourth one has center is the 3rd

Nataliya [291]3 years ago
7 0

Answer:

The correct answer options are B. (x + 9)^2 + (y + 12)^2 = 36 and D. (x + 16)^2 + ( y + 3)^2 = 17.

Step-by-step explanation:

We know that the formula of a circle is (x - h)^2 + (y - k)^2 = r^2 where k is the value of the ordinate, h is the value of the abscissa and r is the radius of the circle.

B. (x + 9)^2 + (y + 12)^2 = 36

[x - (-9)]^2 + [y - (-12)]^2 = 6^2

Center (-9, -12)

D. (x + 16)^2 + ( y + 3)^2 = 17

[x - (-16)]^2 + [y - (-3)]^2 =\sqrt{17}

Center (-16, -3)

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What is log base 7 of 252
rjkz [21]

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2.84

Step-by-step explanation:

Recognize that 252 = 7*36

and so:

log base 7 of 252 = log base 7 of 36 + log base 7 of 7, or

                                 log base 7 of 36 + 1

So the most you can simplify log base 7 of 252 is to write 1 + log base 7 of 36.

Or, if you want to use the change of base formula, you could do the following:

                                 log 36

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and so log base 7 of 252 would come out to

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Check:  does 7^2.84 = 252?  YES.  So we know that:

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