We have been given that :-
The length of a parasite in experiment A is ![2.5 \times 10^{-3}](https://tex.z-dn.net/?f=2.5%20%5Ctimes%2010%5E%7B-3%7D)
The length of a parasite in experiment B is ![1.25 \times 10^{-4}](https://tex.z-dn.net/?f=1.25%20%5Ctimes%2010%5E%7B-4%7D)
Let us write the the length of the parasite in experiment A in the exponent of -3.
![1.25 \times 10^{-4}= 0.125 \times 10^{-3}](https://tex.z-dn.net/?f=1.25%20%5Ctimes%2010%5E%7B-4%7D%3D%200.125%20%5Ctimes%2010%5E%7B-3%7D%20)
Clearly, the length of parasite in experiment A is greater than the length of parasite in experiment B.
The difference in the length is given by
![2.5 \times 10^{-3} -0.125 \times 10^{-4}](https://tex.z-dn.net/?f=2.5%20%5Ctimes%2010%5E%7B-3%7D%20-0.125%20%5Ctimes%2010%5E%7B-4%7D)
![=2.375 \times 10^{-3}](https://tex.z-dn.net/?f=%3D2.375%20%5Ctimes%2010%5E%7B-3%7D)
Therefore, the length of the parasite in experiment A is
inches greater than the length of the parasite in experiment B.
Answer:
-19, -8, 0, 1/4, 1/2 is the correct order
False. This is because no matter what the number is, the properties of multiplication and division stay the same. So, if one odd and even number multiply/divide, then the answer will be negative. But, if two numbers of the same sign (both either negative or positive) are divided/multiplied, they will both be positive. Therefore, the result is not always the same sign as the starting integers
Hope this helped! :D
Answer:
i dont know much detail about this question but it could be 1. simplest answer
Step-by-step explanation:
Radical 63 can be broken down as radical 9 and 7. Radical 9 can be also 3 and you carry the radical 7. So radical 63 is basically 3 radical 7.