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Karo-lina-s [1.5K]
3 years ago
12

If A • B*2 = 1.8 x 10*-7, and C•B/D = 7.2 x 10*-4, find the value of A•D*2/C*2

Chemistry
1 answer:
joja [24]3 years ago
8 0

Answer:

A*D²/C² = 0.347

Explanation:

A*B² = 1.8*10⁻⁷----- (1)

making A subject of formula; A = 1.8 * 10⁻⁷/B² ----(2)

C* B/D = 7.2*10⁻⁴ ----(3)

making C subject of formula; C = D * 7.2*10⁻⁴/B ----(4)

substituting the values of A and C in the equation A*D²/C²

A*D²/C² = (D² * 1.8 * 10⁻⁷/B²)/(D * 7.2*10⁻⁴/B)²

A*D²/C² = (D² * 1.8 * 10⁻⁷/B²)/(D² * 5.184*10⁻⁷/B²)

A*D²/C² = D² * 1.8 * 10⁻⁷/B² * B²/D² * 5.184*10⁻⁷

A*D²/C² = 1.8 * 10⁻⁷/5.184*10⁻⁷

A*D²/C² = 0.347

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Answer:

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3 0
2 years ago
1.15 g of a metallic element needs 300 cm3 of oxygen for complete reaction, at 298 K and 1 atm
sashaice [31]
1) Calculate the number of moles of O2 (g) in 300 cm^3 of gas at 298 k and 1 atm


Ideal gas equation: pV = nRT => n = pV / RT


R = 0.0821 atm*liter/K*mol

V = 300 cm^3 = 0.300 liter

T = 298 K

p = 1 atm


=> n = 1 atm * 0.300 liter / [ (0.0821 atm*liter /K*mol) * 298K] = 0.01226 mol


2) The reaction of a metal with O2(g) to form an ionic compound (with O2- ions) is of the type


X (+) + O2 (g) ---> X2O          or   


2 X(2+) + O2(g) ----> X2O2 = 2XO     or


4X(3+) + 3O2(g) ---> 2X2O3


 
In the first case, 1 mol of metal react with 1 mol of O2(g); in the second case, 2 moles of metal react with 1 mol of O2(g); in the third, 4 moles of X react with 3 moles of O2(g)



So, lets probe those 3 cases.


3) Case 1: 1 mol of metal X / 1 mol O2(g) = x moles / 0.01226 mol

=> x = 0.01226 moles of metal X


Now you can calculate the atomic mass of the hypotethical metal:

1.15 grams / 0.01226 mol = 93.8 g / mol


That does not correspond to any of the metal with valence 1+


So, now probe the case 2.



4) Case 2:


2moles X metal / 1 mol O2(g) = x / 0.01226 mol


=> x = 2 * 0.01226 = 0.02452 mol


And the atomic mass of the metal is: 1.15 g / 0.02452 mol = 46.9 g/mol


That is similar to the atomic mass of titanium which is 47.9 g / mol and whose valece is 2+.


4) Case 3


4 mol meta X / 3 mol O2 = x / 0.01226 => x = 0.01226 * 4 / 3 = 0.01635 


atomic mass = 1.15 g / 0.01635 mol = 70.33 g/mol


That does not correspond to any metal.


Conclusion: the identity of the metallic element could be titanium.
5 0
3 years ago
What is atomic mass?
vovikov84 [41]
Atomic mass is the quantity of protons that have in a atom. Which atom have different numbers of protons, being able to be identified by them.
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Summarize the relationship between an electron's energy level and its location in an atom
FromTheMoon [43]

Answer:

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Explanation:

When an electron is close to the nucleus, it is at as low an energy level as it can get.

We must put energy into an electron to pull it away from the attraction of a nucleus.

So, electrons that are further from the nucleus are at higher energy levels.

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¿Cuáles son las formas alotrópicas del carbono (como se encuentra en la naturaleza)?
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Answer: El carbono, que en estado sólido, puede adoptar muchas formas alotrópicas, siendo las más comunes el diamante (red tridimensional) y el grafito (láminas), aunque también puede formar nanoestructuras en forma de balón de fútbol (fullerenos) o tubos diminutos (nanotubos de carbono), entre otras posibilidades.

Explanation:

3 0
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