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2 years ago

If A • B2 = 1.8 x 10-7, and C•B/D = 7.2 x 10-4, find the value of A•D2/C*2

Chemistry

1 answer:

joja [24]2 years ago

8 0

Answer:

A*D²/C² = 0.347

Explanation:

A*B² = 1.8*10⁻⁷----- (1)

making A subject of formula; A = 1.8 * 10⁻⁷/B² ----(2)

C* B/D = 7.2*10⁻⁴ ----(3)

making C subject of formula; C = D * 7.2*10⁻⁴/B ----(4)

substituting the values of A and C in the equation A*D²/C²

A*D²/C² = (D² * 1.8 * 10⁻⁷/B²)/(D * 7.2*10⁻⁴/B)²

A*D²/C² = (D² * 1.8 * 10⁻⁷/B²)/(D² * 5.184*10⁻⁷/B²)

A*D²/C² = D² * 1.8 * 10⁻⁷/B² * B²/D² * 5.184*10⁻⁷

A*D²/C² = 1.8 * 10⁻⁷/5.184*10⁻⁷

A*D²/C² = 0.347

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2 years ago

The component which dissolves in a solution is called the?

VladimirAG [237]

The correct answer is Solute

Explanation:

In chemistry, a solution refers to a homogenous mixture of two substances that occurs through dissolution, this means once they are mixed the substances form a uniform new substance and cannot be easily separated. Additionally, in chemistry, the substances involved in a solution are either classified as solutes if they are the substances that dissolve to form a solution or as solvents in the case of substances in which the solute dissolves in. For example, if you mix salt and water, the salt acts as the solute while the water is the solvent. Thus, the component which dissolves in a solution is called the solute.

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3 years ago

A 25.0g sample of brass, which has a specific heat capacity of 0.375·J·g−1°C−1, is dropped into an insulated container containin

Angelina_Jolie [31]

Answer:

The equilibrium temperature of water is 25.6 °C

Explanation:

Step 1: Data given

Mass of the sample of brass = 25.0 grams

The specific heat capacity = 0.375 J/g°C

Mass of water = 250.0 grams

Temperature of water = 25.0 °C

The initial temperature of the brass is 96.7°C

Step 2: Calculate the equilibrium temperature

Heat lost = heat gained

Q(sample) = -Q(water)

Q = m*C* ΔT

m(sample)*c(sample)*ΔT(sample) = - m(water)*c(water)*ΔT(water)

⇒m(sample) = the mass of the sample of brass = 25.0 grams

⇒with c(sample) =The specific heat capacity = 0.375 J/g°C

⇒with ΔT = the change of temperature = T2 - T1 =T2 - 96.7 °C

⇒with m(water) = the mass of the water = 250.0 grams

⇒with c(water) = the specific heat capacity = 4.184 J/g°C

⇒with ΔT(water) = the change of temperature of water = T2 - T1 = T2 - 25.0°C

25.0 * 0.375 * (T2 - 96.7) = - 250.0 * 4.184 J/g°C * (T2 - 25.0°C)

9.375T2 - 906.56 = -1046T2 + 26150

9.375T2 + 1046T2 = 26150 + 906.56

1055.375T2 = 27056.26

T2 = 25.6 °C

The equilibrium temperature of water is 25.6 °C

4 0

3 years ago

If 0.2 g of nitrobenzene are added to 10.9 g of naphthalene, calculate the molality of the solution. (given: molar mass of nitro

In-s [12.5K]

Molality is defined as 1 mole of a solute in 1 kg of solvent.

Molality=

$\frac{Number of moles of solute}{Mass of solvent in kg}$

Number of moles of solute, n=

$\frac{Given mass of the substance}{Molar mass of the substance}$

Given mass of the nitrobenzene=0.2 g

Molar mass of the substance= 123.06 g mol⁻¹

Number of moles of nitrobenzene,

$n= \frac{0.2 }{123.06}$

Number of moles of nitrobenzene, n= 0.0016 mol

Mass of 10.9 g of naphthalene in kg=0.0109

$Molality= \frac{0.0016}{0.0109 }$

Molality= 0.146 m

7 0

3 years ago

If A • B*2 = 1.8 x 10*-7, and C•B/D = 7.2 x 10*-4, find the value of A•D*2/C*2

If A • B2 = 1.8 x 10-7, and C•B/D = 7.2 x 10-4, find the value of A•D2/C*2