Question

5. average A body sets off from rest with a constant acceleration of 8.0 m/s? What distance will it have covered after 3.0 s? 6.

Answer 1

Answer:

$\boxed {\boxed {\sf 36 \ meters}}$

Explanation:

We are asked to find the distance a body covers. We know the initial velocity, acceleration, and time, so we will use the following kinematic equation.

$d= v_i t+ \frac {1}{2} \ at^2$

The body starts at rest with an initial velocity of 0 meters per second. The acceleration is 8 meters per second squared. The time is 3.0 seconds.

• $v_i$= 0 m/s
• a= 8 m/s²
• t= 3 s

Substitute the values into the formula.

$d= (0 \ m/s)(3 \ s) + \frac{1}{2} (8 \ m/s^2)(3 \ s)^2$

Multiply the first set of parentheses.

$d= ( 0 \ m/s * 3 \ s) + \frac{1}{2} ( 8 \ m/s^2)(3 \ s)^2$

$d=0 \ m + \frac{1}{2} ( 8 \ m/s^2)(3 \ s)^2$

Solve the exponent.

• (3 s)²= 3 s* 3 s= 9 s²

$d= 0 \ m + \frac{1}{2}( 8 \ m/s^2)(9 \ s^2)$

Multiply again.

$d= 0 \ m + \frac{1}{2} ( 72 \ m)$

$d= 36 \ m$

The body will cover a distance of 36 meters.