Where would you weigh the most?
2 answers:
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Answer:
4s.
Explanation:
Hello,
In this case, considering that the instantaneous acceleration is computed via the change in the velocity divided by the change in the time, at 4 s we can evidence that the instantaneous acceleration is -2m/s² since the initial velocity at t=0s is 8m/s and at t=4s the velocity is 0 m/s, meaning that such decrease accounts for a deceleration process which is represented by a negative acceleration, and the value is:
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Answer:
<em>a) 0.67 rad/sec in the clockwise direction.</em>
<em>b) 98.8% of the kinetic energy is lost.</em>
Explanation:
Let us take clockwise angular speed as +ve
For first cylinder
rotational inertia = 2.0 kg-m^2
angular speed ω = +5.0 rad/s
For second cylinder
rotational inertia = 1.0 kg-m^2
angular speed = -8.0 rad/s
The rotational momentum of a rotating body is given as = ω
where is the rotational inertia
ω is the angular speed
The rotational momenta of the cylinders are:
for first cylinder = ω = 2.0 x 5.0 = 10 kg-m^2 rad/s
for second cylinder = ω = 1.0 x (-8.0) = -8 kg-m^2 rad/s
The total initial angular momentum of this system cylinders before they were coupled together = 10 + (-8) = <em>2 kg-m^2 rad/s</em>
When they are coupled coupled together, their total rotational inertia = 1.0 + 2.0 = 3 kg-m^2
Their final angular rotational momentum after coupling =
where is their total rotational inertia
= their final angular speed together
Final angular momentum = 3 x = 3
According to the conservation of angular momentum, the initial rotational momentum must be equal to the final rotational momentum
this means that
2 = 3
= final total angular speed of the coupled cylinders = 2/3 = <em>0.67 rad/s</em>
From the first statement, <em>the direction is clockwise</em>
b) Rotational kinetic energy =
where is the rotational inertia
is the angular speed
The kinetic energy of the cylinders are:
for first cylinder = =
= 25 J
for second cylinder = = 32 J
Total initial energy of the system = 25 + 32 = 57 J
The final kinetic energy of the cylinders after coupling =
where
where is the total rotational inertia of the cylinders
is final total angular speed of the coupled cylinders
Final kinetic energy = = 0.67 J
kinetic energy lost = 57 - 0.67 = 56.33 J
percentage = 56.33/57 x 100% = <em>98.8%</em>