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Jet001 [13]
3 years ago
6

3. Two cars, both with a mass of 500 kg, are traveling down a road. The first car has a velocity of 65 m/s east and the second c

ar has a velocity of 85 m/s west. (Chapter 2 – Pages 54-55) a. Calculate the momentum of both cars showing the appropriate equation from your textbook and your work with units in order to receive credit. b. Which car has the larger momentum? Explain how you know.
Physics
1 answer:
-BARSIC- [3]3 years ago
6 0

Answer:

32500 kg m/s east, 42500 kg m/s west. Second car has larger momentum

Explanation:

The momentum of an object is given by

p = mv

where

m is the mass

v is the velocity

For the first car, m = 500 kg and v = 65 m/s east, so the momentum is

p_1 = (500)(65)=32500 kg m/s east

For the second car, m = 500 kg and v = 85 m/s west, so the momentum is

p_2 = (500)(85)=42500 kg m/s west

By comparing the two momentum, we see that the second car has larger momentum.

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Answer:

Plane will 741.6959 m apart after 1.7 hour                    

Explanation:

We have given time = 1.7 hr

So if we draw the vectors of a 2d graph we see that the difference in angles is   = 102^{\circ}-65.3^{\circ}=36.7^{\circ}

Speed of first plane  = 730 m/h

So distance traveled by first plane = 730×1.7 = 1241 m

Speed of second plane = 590 m/hr

So distance traveled by second plane = 590×1.7 = 1003 m

We represent these distances as two sides of the triangle, and the distance between the planes as the side opposing the angle 58.6.

Using the law of cosine, r^2 representing the distance between the planes, we see that:

r^2=1241^2+1003^2-2\times 1003\times 1241cos(36.7)=550112.8295

r = 741.6959 m

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Answer:

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Explanation:

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