Question

An archer wishes to shoot an arrow at a target at eye level a distance of 50.0m away. If the initial speed imparted to the arrow is 70.0m/s, what angle should the arrow make with the horizontal as it is being shot?
Physics

Answer 1

Given:
Hmax (distance) = 50.0m
v₀ = 70.0m/s

Required:
what angle should the arrow make with the horizontal as it is being shot

Solution:
Hmax = v₀²sin²θ / 2g
sin²θ = 2gHmax / v₀²
sin²θ = 2 (9.81 m/s²) (50m) / (70 m/s)²
sin²θ = 0.200
θ = 26.56°