An archer wishes to shoot an arrow at a target at eye level a distance of 50.0m away. If the initial speed imparted to the arrow
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Answer:
0.53 m
Explanation:
First of all, we have to consider the vertical motion of the ball, in order to find the time it takes for the marble to reach the ground. The initial height is , the initial vertical velocity is zero, while the acceleration is
, so the vertical position at time t is given by
By demanding y(t)=0, we find the time t at which the ball reaches the ground:
Now we can find the horizontal range of the marble: we know the initial horizontal speed (v=1.24 m/s), we know the total time of the motion (t=0.43 s), and since the horizontal speed is constant, the total distance traveled on the horizontal direction is