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3 years ago

The first 3 questions I really need y’all help on this

Mathematics

2 answers:

max2010maxim [7]3 years ago

5 0

First one is 20
second is 38
and last is 33
you just replace the letter with the number

schepotkina [342]3 years ago

3 0

Answer: 3+ m = 20 4n-2 = 38 2x+21 = 33

Step-by-step explanation:

3+ 17 = 20 4(10) = 40 so 40 -2 equals 38. 2(6) = 12 so 12+21= 33

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Find the exact value of cos(sin^-1(-5/13))

son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

$\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}$

$\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}$

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

8 0

3 years ago

Please help me with this statistical question if you can, it would mean alot im really struggling right now

MA_775_DIABLO [31]

Answer:

vcc bc cvfdf

Step-by-step explanation:

3 0

3 years ago

a geometric series where the first term is -12, the last term is -972, and each term after the first is triple the previous term

Luba_88 [7]

Answer:

the geometric series is a(n) = -12(3)^(n-1)

Step-by-step explanation:

"Triple" denotes multiplication by 3. Thus, the common factor here is 3.

The general formula for a geometric series is a(n) = a(1)(r)^(n-1), where a(1) is the first term, r is the common ratio.

Here, we have a(n)= (-12)(3)^(n-1) = -972.

We need to solve this for n, which represents the last term.

The first step towards solving for n is to divide both sides by -12:

3^(n-1) = 81

To solve for n-1, rewrite 81 as 3^4. Then we have:

3^(n-1) = 3^4, implying that (n-1) = 4 and that n = 5.

Then we know that it is the 5th term that equals -972.

In summary, the geometric series is a(n) = -12(3)^(n-1).

8 0

3 years ago

Catering the concord theater serves punch during intermission. If each of 200 people think 1 c of punch, how many gallons of pun

Delicious77 [7]

Answer:

they will need 2 gallons of punch

3 0

3 years ago

Which of the following are equivalent ratios? 15 to 20 6 to 8 8 to 12 9 to 12

I am Lyosha [343]

So yuo simplyfly

15:20=3:4

6:8=3:4

8:12=2:3

9:12=3:4

so your answer is not c

3 0

3 years ago

Read 2 more answers