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allochka39001 [22]
3 years ago
12

Magnetism, reactivity, and fluorescence are three special properties used to identify minerals. Please select the best answer fr

om the choices provided
True
or False
Physics
2 answers:
Dominik [7]3 years ago
6 0

Answer:true

Explanation: test

astraxan [27]3 years ago
3 0

Answer: True

Explanation: Following are the properties that are used to identify minerals:

(1) Color

(2) Hardness

(3) Magnetism : It is the property of mineral to attract or repel with other magnetic materials.

(4) Luster : It is the property that shows the surface is reflecting light or not.

(5) Reactivity: Reactivity is also responsible to identify mineral. How the mineral is reacting with acids, bases etc helps to identify type of minerals.

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One factor of x^3-3x^2-4x+12 is x+2. find the remaining factors
telo118 [61]
Dividing  x^3 - 3x^2 - 4x + 12 by x + 2 gives

x^2 -5x + 6

= (x - 3)(x - 2)

so remaining factors are    x - 3 and x - 2 answer
6 0
3 years ago
A 52–newton bird feeder is tied to a cord, which is attached to a tree branch. Describe the tension force of the rope.
iris [78.8K]
If you are given a 52 Newton bird feeder tied to a cord, it means that it has a weight of 52 Newton. Since the bird feeder is not moving, we assume it to exert a force downward, that is its weight, and the cord that ties it, the force is upward. This upward force is the tension and is therefore equal to 52N.
4 0
3 years ago
Read 2 more answers
An object of mass 2kg is on an incline where there is an applied force of 15N. The
seraphim [82]

a) See free-body diagram in attachment

b) The acceleration is 2.46 m/s^2

Explanation:

a)

The free-body diagram of an object is a diagram representing all the forces acting on the object. Each force is represented by a vector of length proportional to the magnitude of the force, pointing in the same direction as the force.

The free-body diagram for this object is shown in the figure in attachment.

There are three forces acting on the object:

  • The weight of the object, labelled as mg (where m is the mass of the object and g is the acceleration of gravity), acting downward
  • The applied force, F_a, acting up along the plane
  • The force of friction, F_f, acting down along the plane

b)

In order to find the acceleration of the object, we need to write the equation of the forces acting along the direction parallel to the incline. We have:

F_a - F_f - mg sin \theta = ma

where:

F_a = 15 N is the applied force, pushing forward

F_f = 5 N is the frictional force, acting backward

mg sin \theta is the component of the weight parallel to the incline, acting backward, where

m = 2 kg is the mass of the object

g=9.8 m/s^2 is the acceleration of gravity

\theta=15^{\circ} is the angle between the horizontal and the incline (it is not given in the problem, so I assumed this value)

a is the acceleration

Solving for a, we find:

a=\frac{F_a - F_f - mg sin \theta}{m}=\frac{15-5-(2)(9.8)(sin 15^{\circ})}{2}=2.46 m/s^2

Learn more about inclined planes:

brainly.com/question/5884009

#LearnwithBrainly

8 0
3 years ago
Which one of the following is radical?<br>a.NH4+<br>b.CUSO4<br>c.CH4<br>d.NH3​
klio [65]

Answer:

The unit that is a radical among the options is;

a. NH₄⁺

Explanation:

A radical is an atom, group of atoms molecule or ion that contains an electron that is unpaired. The presence of the unpaired electrons make radical very reactive as such most radicals enter into reactions with other species or with themselves to form new compounds making them not last long.

Radicals are also known as free radicals. Examples of radicals includes; Ammonium ion, NH₄⁺

Nitrate ion NO₃⁻ (From a salt)

Hydroxide ion OH⁻ (From a base)

Sulphate ion SO₄²⁺ (From an acid)

All of which are formed in aqueous solution of acids, salts and bases.

5 0
3 years ago
Two arrows are shot vertically upward. the second arrow is shot after the first one, but while the first is still on its way up.
Neko [114]
<span>Now that you know the time to reach its maximum height, you have enough information to find out the initial velocity of the second arrow. Here's what you know about it: its final velocity is 0 m/s (at the maximum height), its time to reach that is 2.8 seconds, but wait! it was fired 1.05 seconds later, so take off 1.05 seconds so that its time is 1.75 seconds, and of course gravity is still the same at -9.8 m/s^2. Plug those numbers into the kinematic equation (Vf=Vi+a*t, remember?) for 0=Vi+-9.8*1.75 and solve for Vi to get....... 17.15 m/s</span>
7 0
3 years ago
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