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3 years ago

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A strong lightning bolt transfers an electric charge of about 16 C to Earth (or vice versa). How many electrons are transferred?

Avogadro’s number is 6.022 × 1023 /mol, and the elemental charge is 1.602 × 10−19 C.

1 answer:

zzz [600]3 years ago

3 0

Answer:

Number of electrons, $n=9.98\times 10^{19}$

Explanation:

A strong lightning bolt transfers an electric charge of about 16 C to Earth, q = 16 C

We need to find the number of electrons that transferred. Let there are n electrons transferred. It is given by using quantization of electric charge as :

q = ne

$n=\dfrac{q}{e}$

e is elemental charge

$n=\dfrac{16}{1.602\times 10^{-19}}$

$n=9.98\times 10^{19}$

So, there are $9.98\times 10^{19}$ electrons that gets transferred. Hence, this is the required solution.

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A 6.00 kg crate is suspended from the end of a short vertical rope of negligible mass. An upward force F(t) is applied to the en

Jlenok [28]

Answer:

$F=52.1301\ N$

Explanation:

Given:

mass attached to the rope, $m=6\ kg$

given time, $t=4.4\ s$

function of height of the mass connected via a rope:

$y=2.8\ t+0.61\ t^3$

differentiate the above eq. with respect to time t gives us the velocity in vertical direction:

$v_y=\frac{d}{dt} y$

$v_y=2.8+1.83\ t^2$

put the value of given time:

$v_y=2.8+1.83\times 4.4^2$

$v_y=38.2288\ m.s^{-1}$

As we know form the Newton'a second law of motion that the rate of change in momentum is proportional to the applied force.

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A quantity of gas has a volume of 0.20 cubic meter and an absolute temperature of 333 degrees kelvin. When the temperature of th

Nesterboy [21]

Answer:

Option C is the correct answer.

Explanation:

By Charles's law we have

V ∝ T

That is

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

Here given that

V₁ = 0.20 cubic meter

T₁ = 333 K

T₂ = 533 K

Substituting

$\frac{V_1}{T_1}=\frac{V_2}{T_2}\\\\\frac{0.20}{333}=\frac{V_2}{533}\\\\V_2=\frac{0.20}{333}\times 533=0.3198m^3$

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Option C is the correct answer.

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Oduvanchick [21]

Answer:

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Explanation:

$u_x$ = Initial velocity of the fish = 1.52 m/s

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$u_y$ = Initial velocity in y axis = 0

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Answer:

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