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Hatshy [7]
2 years ago
10

Determine the tension developed in cables OD and OB and the strut OC, required to support the 500-lb crate. The spring OA has an

unstretched length of 0.2 ft and a stiffness of kOA

Physics
1 answer:
natali 33 [55]2 years ago
6 0

Answer:Fob= 86.2 lb, Foc= 175 lb, Fod= 506 lb

Explanation:firstly we need to get the spring stretch by subtracting the unstretched length from 1. The result will be (1-0.2=0.8ft). We then get the spring force by multiplying kOA by 0.8ft. therefore the spring force will be {350x0.8}= 280 lb. After that we can resolve each force as shown in the attachment.

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Avery likes to walk 30 feet in 10<br>seconds. What is her speed?​
Sliva [168]

Answer:

If she is walking 30 feet every 10 seconds, that means she is walking 180 feet per minute. Multiply that by the 60 minutes in an hour, means she walks (180x60)= 10,800 feet an hour.

She walks 3 feet a second.

She walks 180 feet a minute.

She walks 10,800 feet an hour.

Explanation:

6 0
3 years ago
Assume that you can heat water with perfect insulation (all the heat from combustion of ethanol is transferred to water). What i
krok68 [10]

Answer:

volumme =0.36 ml

Explanation:

total heat required can be obtained by using following formula

q= mC \Delta T.......(1)

where,

m - mass of water,

C - specific heat capacity of water and = 4.184 j g^{-1} °C

\Delta T - total change in temperature.  = 10°C

The density of water is 1 g/cc. hence, 200 mL of water is equal to 200 g

putting all value in the above equation (1)

q = 200*4.184* 10 ° = 8368 J.

Therefore total number of moles of ethanol required to supply 8368 J of heat is

\frac {8368}{1368000} = 0.006117 moles.

The molar mass of ethanol is 46 g/mol.

The mass of ethanol required is 46* 0.006117 = 0.28138 g

The density of ethanol is 0.78 g/ml.

The volume of ethanol required is

\frac {0.28138}{0.78} = 0.36 ml

8 0
3 years ago
If a single circular loop of wire carries a current of 62 A and produces a magnetic field at its center with a magnitude of 1.20
s2008m [1.1K]

Given Information:  

Current in loop = I = 62 A

Magnitude of magnetic field = B = 1.20x10⁻⁴ T

Required Information:  

Radius of the circular loop = r = ?  

Answer:  

Radius of the circular loop = 0.324 m

Explanation:  

In a circular loop of wire with radius r and carrying a current I  induces a magnetic field B which is given by

B = μ₀I/2r

Please note that for an infinitely straight long wire we use 2πr whereas for circular loop we use 2r

Where μ₀= 4πx10⁻⁷ is the permeability of free space

Re-arranging the equation yields

r = μ₀I/2B

r = 4πx10⁻⁷*62/2*1.20x10⁻⁴

r = 0.324 m

Therefore, the radius of this circular loop is 0.324 m

3 0
3 years ago
The atmospheric pressure above a swimming pool changes from 753 to 772 mm of mercury. the bottom of the pool is a rectangle (11
Evgesh-ka [11]
Change in pressure : 772-753 = 19 mm Hg 
Since 1 mm Hg = 133 Pa Hg
 Then, 19 mm Hg = 2527 Pa Hg
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5 0
2 years ago
Read 2 more answers
When is kinetic energy transferred from one object to another? Question 24 options:
postnew [5]
When two objects collide is the answer...Hope this helps :)
7 0
3 years ago
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