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Hatshy [7]
3 years ago
10

Determine the tension developed in cables OD and OB and the strut OC, required to support the 500-lb crate. The spring OA has an

unstretched length of 0.2 ft and a stiffness of kOA

Physics
1 answer:
natali 33 [55]3 years ago
6 0

Answer:Fob= 86.2 lb, Foc= 175 lb, Fod= 506 lb

Explanation:firstly we need to get the spring stretch by subtracting the unstretched length from 1. The result will be (1-0.2=0.8ft). We then get the spring force by multiplying kOA by 0.8ft. therefore the spring force will be {350x0.8}= 280 lb. After that we can resolve each force as shown in the attachment.

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Infer​ the effect of deforestation on the carrying capacity of the Amazon rainforest.
RUDIKE [14]

Answer:

More than 20% of the amazon has been destroyed, affects biodiversity.

Explanation:

  • The biggest issues that the amazon is facing is the deforestation and it involves the clearing of land areas for logging, farming, and other land-use changes.
  • Effects that are seen are droughts, floods, destruction of habitats of flora and fauna along with the valuable services of the ecosystem.
  • This leads to a decrease in the carrying capacity of the species and the decline of the essential resources that are necessary to survive.
4 0
3 years ago
What is night vision pls tell fast
mario62 [17]

Answer:

Night vision is when you can see in the dark or at night like owls

Explanation:

3 0
3 years ago
Read 2 more answers
What is the approximate size of the Earth's magnetic field? (dont ask me to specify thats what the question is and im as confuse
Olegator [25]

Answer:

The Earth's magnetic field intensity is roughly between 25,000 - 65,000 nT (.25 -.65 gauss).

Explanation:

<em>To measure the Earth's magnetism in any place, we must measure the direction and intensity of the field. The Earth's magnetic field is described by seven parameters. These are declination (D), inclination (I), horizontal intensity (H), the north (X), and east (Y) components of the horizontal intensity, vertical intensity (Z), and total intensity (F). The parameters describing the direction of the magnetic field are declination (D) and inclination (I). D and I are measured in units of degrees, positive east for D and positive down for me. The intensity of the total field (F) is described by the horizontal component (H), vertical component (Z), and the north (X) and east (Y) components of the horizontal intensity. These components may be measured in units of gauss but are generally reported in nanoTesla (1nT * 100,000 = 1 gauss). </em><em>The Earth's magnetic field intensity is roughly between 25,000 - 65,000 nT (.25 - .65 gauss). </em><em>Magnetic declination is the angle between magnetic north and true north. D is considered positive when the angle measured is east of true north and negative when west.  The magnetic inclination is the angle between the horizontal plane and the total field vector, measured positive into Earth. In older literature, the term “magnetic elements” is often referred to as D, I, and H.</em>

8 0
3 years ago
How can you decrease the momentum of an object?
mamaluj [8]
You will have to "put force against the object to slow it down." Momentum is the force that is keeping a object moving in a certain direction so if you would want to slow down the object you will have to put another force against the object to slow it down or stop it. For example: a person kicks a ball, the ball moving is the momentum. So, if you would want to stop the ball you would have t put something in its path to slow it down which is the decreasing of it's momentum. Therefore you would put a bump in the wall and when the ball hits the bump it slows down.

Hope this helps!
7 0
3 years ago
Read 2 more answers
Can someone help?
laila [671]

Answer:

i) 21 cm

ii) At infinity behind the lens.

iii) A virtual, upright, enlarged image behind the object

Explanation:

First identify,

object distance (u) = 42 cm (distance between  object and lens, 50 cm - 8 cm)

image distance (v) = 42 cm (distance between  image and lens, 92 cm - 50 cm)

The lens formula,

\frac{1}{v} -\frac{1}{u} =\frac{1}{f}

Then applying the new Cartesian sign convention to it,

\frac{1}{v} +\frac{1}{u} =\frac{1}{f}

Where f is (-), u is (+) and  v is (-) in  all 3  cases. (If not values with signs have to considered, this method that need will not arise)

Substituting values you get,

i) \frac{1}{42} +\frac{1}{42} =\frac{1}{f}\\\frac{2}{42} =\frac{1}{f}

f = 21 cm

ii) u =21 cm, f = 21 cm v = ?

Substituting in same equation\frac{1}{v} =\frac{1}{21} =\frac{1}{21} \\\\\frac{1}{v} = 0\\

  v ⇒ ∞ and image will form behind the lens

iii) Now the object will be within the focal length of the lens. So like in the attachment, a virtual, upright, enlarged image behind the object.

7 0
3 years ago
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