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tensa zangetsu [6.8K]
3 years ago
15

for the reactants represented by the equation 2H2 + O2 > 2H2O, how many grams of water are produced from 376.97 mol of hydrog

en?
Chemistry
2 answers:
Hunter-Best [27]3 years ago
8 0

Answer:

6792.1 g

Explanation:

Dimensional analysis:

376.92 mol H2 * (2 mol h2o / 2 mol h2) * (18.02g h2o / 1 mol h2o)

6792.1 g

kirza4 [7]3 years ago
6 0

Answer:

Amount of water produced from 376.97 mole hydrogen is 6785.46 g

Explanation:

Given number of moles of hydrogen = 376.97 mole

The balanced reaction is shown below

2\textrm{H}_{2}\left ( g \right )+\textrm{O}_{2}\left ( g \right )\rightarrow 2\textrm{H}_{2}\textrm{O}\left ( l \right )

2 mole of water is produced from 2 mole of hydrogen gas according to the balanced reaction.

Number of moles of water produced by 376.97 mole hydrogen = 376.97 mole

Molar mass of water = 1 8 g/mol

\textrm{Amount of water produced} = \left ( 376.97 \textrm{ mole}\times 18\textrm{ g/mol} \right ) = 6785.46 \textrm{ g}

Amount of water produced = 6785.46 g

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Vedmedyk [2.9K]
The ideal gas law may be written as
p= \frac{\rho R T}{M}
where
p = pressure
ρ =density
T = temperature
M = molar mass
R = 8.314 J/(mol-K)

For the given problem,
ρ = 0.09 g/L = 0.09 kg/m³
T = 26°C = 26+273 K = 299 K
M = 1.008 g/mol = 1.008 x 10⁻³ kg/mol

Therefore
p= \frac{(0.09 \, kg/m^{3})*(8.314 \, J/(mol-K))*(299 \, K)}{1.008 \times 10^{-3} \, kg/mol} =2.2195 \times 10^{5} \, Pa

Note that 1 atm = 101325 Pa
Therefore
p = 2.2195 x 10⁵ Pa
   = 221.95 kPa 
   = (2.295 x 10⁵)/101325 atm
   = 2.19 atm

Answer:
2.2195 x 10⁵ Pa (or 221.95 kPa or 2.19 atm)

4 0
3 years ago
Specific gravity of a vegetable oil is 0.85. What is its density?
elena-s [515]
I think its density is 850kg/m^3
6 0
2 years ago
Consider the reaction given below.
Drupady [299]

Answer:

  • <u>K =  0.167 s⁻¹</u>

Explanation:

<u>1) Rate law, at a given temperature:</u>

  • Since all the data are obtained at the same temperature, the equilibrium constant is the same.

  • Since only reactants A and B participate in the reaction, you assume that the form of the rate law is:

        r = K [A]ᵃ [B]ᵇ

<u>2) Use the data from the table</u>

  • Since the first and second set of data have the same concentration of the reactant A, you can use them to find the exponent b:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₂ = (1.50)ᵃ (2.50)ᵇ = 2.50 × 10⁻¹ M/s

         Divide r₂ by r₁:     [ 2.50 / 1.50] ᵇ = 1 ⇒ b = 0

  • Use the first and second set of data to find the exponent a:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₃ = (3.00)ᵃ (1.50)ᵇ = 5.00 × 10⁻¹ M/s

        Divide r₃ by r₂: [3.00 / 1.50]ᵃ = [5.00 / 2.50]

                                  2ᵃ = 2 ⇒ a = 1

         

<u>3) Write the rate law</u>

  • r = K [A]¹ [B]⁰ = K[A]

This means, that the rate is independent of reactant B and is of first order respect reactant A.

<u>4) Use any set of data to find K</u>

With the first set of data

  • r = K (1.50 M) = 2.50 × 10⁻¹ M/s ⇒ K = 0.250 M/s / 1.50 M = 0.167 s⁻¹

Result: the rate constant is K =  0.167 s⁻¹

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Though it is believed that using the dam as a power generation or hydroelectric power supply generates no greenhouse gases, it, however, has many disadvantages which make it deemed not suitable or sustainable for use in the contemporary time.

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