Question

for the reactants represented by the equation 2H2 + O2 > 2H2O, how many grams of water are produced from 376.97 mol of hydrogen?

Answer 1

Answer:

6792.1 g

Explanation:

Dimensional analysis:

376.92 mol H2 * (2 mol h2o / 2 mol h2) * (18.02g h2o / 1 mol h2o)

6792.1 g

Answer 2

Answer:

Amount of water produced from 376.97 mole hydrogen is 6785.46 g

Explanation:

Given number of moles of hydrogen = 376.97 mole

The balanced reaction is shown below

$2\textrm{H}_{2}\left ( g \right )+\textrm{O}_{2}\left ( g \right )\rightarrow 2\textrm{H}_{2}\textrm{O}\left ( l \right )$

2 mole of water is produced from 2 mole of hydrogen gas according to the balanced reaction.

Number of moles of water produced by 376.97 mole hydrogen = 376.97 mole

Molar mass of water = 1 8 g/mol

$\textrm{Amount of water produced} = \left ( 376.97 \textrm{ mole}\times 18\textrm{ g/mol} \right ) = 6785.46 \textrm{ g}$

Amount of water produced = 6785.46 g