Answer:
6.66 s will it take for [AB] to reach 1/3 of its initial concentration 1.50 mol/L.
Explanation:
The order of the reaction is 2.
Integrated rate law for second order kinetic is:
Where, is the initial concentration = 1.50 mol/L
is the final concentration = 1/3 of initial concentration = = 0.5 mol/L
Rate constant, k = 0.2 L/mol*s
Applying in the above equation as:-
<u>6.66 s will it take for [AB] to reach 1/3 of its initial concentration 1.50 mol/L.</u>
1p is not possible because it goes like this 1s2 2s2 2p6
Answer:
yep
Explanation:
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Answer:
Mass of arsenic chloride produced is 0.363 g
Explanation:
Given data:
Mass of arsenic chloride produced = ?
Mass of arsenic react = 0.150 g
Mass of chlorine = excess
Solution:
Chemical equation:
2As + 3Cl₂ → 2AsCl₃
First of all we will calculate the number of moles of arsenic.
Number of moles = mass/ molar mass
Number of moles = 0.150 g/ 75 g/mol
Number of moles = 0.002 mol
Now we will compare the moles of arsenic with arsenic chloride.
As : AsCl₃
2 : 2
0.002 : 0.002
Mass of arsenic chloride produced:
Mass = number of moles × molar mass
Mass = 0.002 × 181.28 g/mol
Mass = 0.363 g