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frosja888 [35]
4 years ago
13

What is the mass of one mole of popcorn kernels? (sig fig hint: consider the precision of avogadro's number to determine the cor

rect number of sig figs.)?
Chemistry
2 answers:
sweet-ann [11.9K]4 years ago
7 0

Answer:

m=7.0106x10^22g

Explanation:

Hello,

In this case we must take into account that the average mass of a dozen popcorn kernels is 1.416 g, therefore, the average mass of one popcorn kernel is:

m=1.416g/12=0.118g

Now, we also know that one mole of popcorn kernels has 6.022x10²³ popcorn kernels, therefore the mass of one mole of popcorn kernels is computed as shown below:

m=1mol*\frac{6.022x10^{23}popcorn \ kernels }{1mol}*\frac{0.118g}{1popcorn\ kernels} \\m=7.0106x10^22g

Best regards.

svetlana [45]4 years ago
4 0

Since the mass of a single popcorn kernel is not given, lets us assume that it is 1 gram

Now:

1 mole of popcorn kernels contain 6.023 * 10^{23} kernels

Since:

1 kernel weighs 1 gram

Then,

1 mole = 6.023 *10^{23} kernels would weigh 6.023 * 10^{23} grams

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A buffer is composed of nh3 and nh4cl. How would this buffer solution control the ph of a solution when a small amount of a stro
Shkiper50 [21]

Answer:

According to Le-chatelier principle, equilibrium will shift towards left to minimize concentration of OH^{-} and keep same equilibrium constant

Explanation:

In this buffer following equilibrium exists -

NH_{3}(aq.)+H_{2}O(l)\rightleftharpoons NH_{4}^{+}(aq.)+OH^{-}(aq.)

So, OH^{-} is involved in the above equilibrium.

When a strong base is added to this buffer, then concentration of OH^{-} increases. Hence, according to Le-chatelier principle, above equilibrium will shift towards left to minimize concentration of OH^{-} and keep same equilibrium constant.

Therefore excess amount of OH^{-} combines with NH_{4}^{+} to produce ammonia and water. So, effect of addition of strong base on pH of buffer gets minimized.

5 0
3 years ago
What coefficient is missing in C2H4 + (?)O2 → 2CO2 + 2H2O?
Daniel [21]

Answer:

3

Explanation:

you must multiply everything out till everything is equal on both sides

7 0
3 years ago
When 3.93 grams of lactic acid, CHoOs(s), are burned in a bomb
aliya0001 [1]

The heat released in the combustion of lactic acid is absorbed by the

calorimeter and in the decomposition of the lactic acid.

ΔH°f of lactic acid is approximately <u>-716.2 kJ</u>

Reasons:

Known parameters are;

Mass of the lactic acid = 3.93 grams

Heat  capacity of the bomb calorimeter = 10.80 kJ·K⁻¹

Change in temperature of the calorimeter, ΔT = 5.34 K

ΔHrxn = ΔErxn

ΔH°f of H₂O(l) = -285.8 kJ·mol⁻¹

ΔH°f of CO₂(g) = -393.5 kJ·mol⁻¹

The chemical equation for the reaction is presented as follows;

  • C₃H₆O₃ + 2O₂ → 3CO₂ + 3H₂O

The heat of the reaction = 10.80 kJ·K⁻¹ × 5.34 K = 57.672 kJ

Molar mass of C₃H₆O₃ = 90.07 g/mol

Number of moles of C₃H₆O₃ = \dfrac{3.93 \, g}{90.07 \, g/mol} = 0.043633 moles

Number of moles of CO₂ produced = 3 × 0.043633 moles = 0.130899 moles

Heat produced = 0.130899 mole × -285.8 kJ·mol⁻¹ = -37.4109342 kJ

Moles of H₂O produced = 0.130899 moles

Heat produced = 0.130899 mole × -393.5 ≈ -51.51 kJ

Therefore, we have;

Heat absorbed by the lactic acid = ΔH°f of H₂O + ΔH°f of CO₂ + Heat absorbed by the calorimeter

Which gives;

Heat absorbed by lactic acid  = -37.4109342 kJ - 51.51 kJ + 57.672 kJ ≈ -31.249 kJ

The heat absorbed by the lactic acid ≈ -31.249 kJ

  • \Delta H^{\circ}f \ of \ C_3H_6O_3 = \dfrac{-31.249}{0.043633} \approx  -716.2

ΔH°f of C₃H₆O₃ ≈ -716.2 kJ

Heat of formation of lactic acid ≈ <u>-716.2 kJ</u>.

Learn more here:

brainly.com/question/13185938

5 0
2 years ago
What force is causing The object to eventually stop moving
hichkok12 [17]

Answer:

Hey buddy, here is your answer. Hope it helps you.

Explanation:

The force stopping the object's motion might be an obvious one - the ground! Friction is a force that slows or stops motion. Friction is the resistance to motion created by two objects rubbing against each other (the sled and the snow, for instance). Even air causes friction.

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3 years ago
What occurs when a magnesium atom becomes a magnesium ion
Karo-lina-s [1.5K]
The electrons are lost.
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